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5 votes

Wizard of subsets

Very similar to @loopy-walt solution, but still OC :)
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6 votes

Wizard of subsets

Move those marked l to the left, then the rs right and then the us up.
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8 votes

Wizard of subsets

Unless I'm missing something
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1 vote

Save now! All the digits at half the price

A bit messier than I'd like, but here goes. As other answers have noted, the doubleable PD10 numbers we want are those where Let's show that every such number can be specified by: for an overall ...
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2 votes

Save now! All the digits at half the price

Other reasoning, same result:
  • 6,847
5 votes

Save now! All the digits at half the price

Let's define some terms: Now we can begin. Let's break the problem down now. Now for the final count!
5 votes

Save now! All the digits at half the price

My guess is: First, observe that the first digit of $x$: Then, the reasoning goes this way: I'm not 100% sure of my calculus but this is how I did it:
  • 51
9 votes
Accepted

Clock hands at right angle

Here is a way I like to think about it Where does your reasoning fall down
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2 votes

How Many Magic Hexagons that use repeated digits?

Question 3 Is it possible to construct a Magic hexagon that uses repeated digits within the grid but doesn't have any repeated digits within any row columns or diagonal line?
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3 votes
Accepted

How Many Magic Hexagons that use repeated digits?

Question 1 How many unique patterns are there that use repeating consecutive digits?
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6 votes
Accepted

Twenty-four coins

Here's an algorithm that requires maximum 7 measurements (I believe): Let's first set some terminology, note that each measurement of n coins can be one of 4 cases: Case 0: All standard coins M = n.s ...
0 votes

What's the fewest weights you need to balance any weight from 1 to 40 pounds?

Once we have determined that the weights must be 1, 3, 9 and 27 grams, an obvious question to ask is how to use these weights to weigh an object. One method, which is my candidate for most efficient, ...
3 votes

Twenty-four coins

An attempt to solve it with 7 measurements Part 1 : possibility analysis Part 2 : an (approximate) lower bound Part 3: A strategy to (attempt to) get an actual solution with 7 measurements. Part 4a ...
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1 vote

Colour the positive integers without making a blue equation

How many? Why (smaller cases)? The working case:
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