34
votes
Accepted
Largest number possible with +, -, ÷
Is there anything in the rules preventing us from simply doing
?
25
votes
Accepted
14
votes
13
votes
Accepted
Unorthodox angle measuring device
The device is a:
Then:
This device also fits the three hints:
12
votes
Accepted
Rearrange these numbers and symbols to make a true equation
The answer is:
We know that there's something tricky because:
Incidentally,
11
votes
Accepted
Maximizing the common value of both sides of an equation (part 2)
We can do
which is pretty large, indeed.
If I'm getting the (rather tricky) maths right the value is between
10
votes
Maximizing the common value of both sides of an equation (part 2)
Sorry I missed the fifth arithmetic operation --- power, and thanks for @franck vivien's advice! Here is my update:
And, as a supplement, in order to see the order of magnitude comparisons...
10
votes
Accepted
9
votes
8
votes
6
votes
5
votes
Accepted
Overlap two Chess Games
This seems closely related to the two king task. The optimal solution by G.Ponzetto
Game 1:
together with a trivial
Game 2:
should be pretty hard to beat.
Total number of half moves: 34
5
votes
Fill a grid with numbers so that each row/column calculation yields the same number
One possible solution is:
I found this by
I'm not sure
5
votes
Four out puzzle: Get rid of a six digit number in 4 moves
This is not always possible (under the assumption that every intermediate result must be an integer, which can likely be removed). In order to reach exactly zero, the last operation must have been a ...
5
votes
Fill a grid with numbers so that each row/column calculation yields the same number
It is possible to find a solution by hand using more logic and less bruteforcing/guessing.
First use Someone's insight:
Also note the number 5:
and the symmetry of the grid:
Make an educated guess:
...
5
votes
Maximizing the common value of both sides of an equation
This is a small improvement on franck vivien's answer. If you upvote this, please also upvote theirs.
The equation
has value
5
votes
Accepted
4
votes
Maximizing the common value of both sides of an equation (part 2)
Pretty sure you can get a lot bigger than this, but..
which is
4
votes
Unorthodox angle measuring device
Not an exact solution, but worth a try
Could you be using a
How?
The issue I have is
4
votes
3
votes
Fill a grid with numbers so that each row/column calculation yields the same number
Nothing clever here, just a programmed evaluation of all permutations.
There are three essentially different solutions:
Each of these can be manipulated through row/column swaps and/or reflection ...
3
votes
Overlap two Chess Games
Here's my silly attempt:
Game A:
Final position in Game A:
Game B:
Combining these two positions will then yield the Maximum Synergy Bongcloud:
which is (always) a legal position. (White will need ...
3
votes
Accepted
It’s the transition that matters
As per the hint, divide the number by 103 if it's an exact multiple, and otherwise subtract 101. Keep repeating this and after 368 operations, the number becomes 1. The fact that both operations ...
3
votes
Maximizing the common value of both sides of an equation (part 2)
Here are my attempts:
which is between
2
votes
2
votes
Unorthodox angle measuring device
I'm not really sure about the precision/accuracy but I think this could be on the right track. If not the correct method, then at least that it's related to the
If we convert the first term in each ...
1
vote
Unorthodox angle measuring device
Don't know such a device, but it's technically possible:
...
1
vote
Accepted
Fill a grid with numbers so that each row/column calculation yields the same number
Based on other answers that already classified all solutions to the original puzzle, here is an observation that one can solve the puzzle with an additional constraint. Namely one can request that all ...
1
vote
A variant of the 2-Chess Games overlapped
Note: I assume the discarded kings to be exempt from the no-collision rule.
Game 1:
Game 2:
I do not claim minimality.
Overlay Game 2 pieces circled:
Only top scored, non community-wiki answers of a minimum length are eligible
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