29

The given sum is what we would get if we were to compute the definite But we can also compute this directly: Now by amazing coincidence $9.3$ squared happens to evaluate to which is good enough to pass for $86.5$. One more lucky coincidence: $9.3$ is easily multiplied by $\frac 23$. So we need to do $6.2$ times $86.5$ which yields The $.3$ cancels ...


8

I finally got it! Below is a detailed explanation


8

Four circles: Five circles: Six circles:


7

I'll take a shot at it Arrived at as follows First Then So But So


4

Best I've found so far is but I haven't exhausted alternatives just yet


2

Could it be: If so,


1

Sure, a 1×4√5 rectangle and a 1×√5 rectangle.


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