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For puzzles about forming numbers using other numbers and mathematical operations.

6
votes
Partial Answer: I'll start with the last one because it looks easier: Now we have: Other restrictions. Now we have : Now we have: Further on: That's it for now. I will t …
answered Aug 19 '16 by Marius
4
votes
There are multiple solutions: Here are two I quickly found: . Reasoning: Working on the multiplication.
answered Oct 26 '16 by Marius
48
votes
I tried to make a digital clock. $0 = (7 + 1 + 2) \times 0$ $1 = (2 + 7 + 1) ^ 0$ $2 = (7 + 1) \times 0 + 2$ $3 = 7 \times 0 + 2 + 1$ $4 = 2 \times 7 - 10$ $5 = 7 - 2 + 1 \times 0$ $6 = 7 - 1 + 2 \ti …
answered Dec 13 '16 by Marius
15
votes
A more elegant way to get all the numbers from 1 to 100 if we allow logarithms and the use of lg as logarithm in base 10 is this (I know, I know, it looks like cheating a bit but it's beautiful) $x = …
answered Aug 21 '17 by Marius
1
vote
One answer: Second one: And a third one: [EDIT] Bonus one or two:
answered Mar 11 '16 by Marius
3
votes
38
votes
$\begin{align} 0 & = (1 + 2 - 3) \times (4 + 5) \\ 1 & = 1 + (2+3-5) \times 4 \\ 2 & = 2 + (1+3-4) \times 5 \\ 3 & = 1 -2+3-4+5 \\ 4 & = 1 \times (2+3-5) + 4 \\ 5 & = 1-2-3+4+5 \\ 6 & = 5+1 \times ( …
answered Mar 20 '17 by Marius
3
votes
One solution I found: Numbers in bold represent the predefined values. Strategy. I took all the 5 digit prime numbers from here Bonus: Here are all the numbers that can be used in such puzz …
answered Aug 23 '17 by Marius
7
votes
It is not possible to generate all the numbers with only the give operations. I used a computer for that. The only ones are 1,2,3,4,6,7,8,9,10,12,15,16,17,19,24,32,48,56,63,64,65,72,80,87,88,89 (marke …
answered Oct 4 '17 by Marius
7
votes
Found it: My pseudo-strategy I've used a "learning algorithm" At first I took blind stabs at short words randomly, trying to use the smaller numbers IVXL That backfired quickly since the letters di …
answered Apr 21 '17 by Marius
9
votes
Nobody is going to check this anyway, but here it goes. I hope all the math is right. $1 = 9 / 9 + 1 - 1$ $2 = 9 / 9 * 1 + 1$ $3 = 9 / 9 + 1 + 1$ $4 = (1+1)^2 - 9 + 9$ $5 = (1+1)^2 + 9 /9$ $6 = (9*9 …
answered Mar 9 '16 by Marius
1
vote
Easy 4 with 4 ones with out addition Medium: 4 with 4 ones without addition, negation, or factorial. Hard: 4 with 4 ones without addition and factorial, using only one subtraction and one ne …
answered Mar 24 '17 by Marius
3
votes
Solutions : Explanation: We can simplify the equation by reducing the letters that appear on the same column with + and - and we get ABC00B + B0CAB - C000C = CCCCCC B+B and C+C end up …
answered Aug 29 '17 by Marius
9
votes
Partial math solutions for the default grid: Reasoning: Still working on the "mutated" grid.
answered Aug 23 '16 by Marius

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