There are 9 equally sized matchsticks, move 2 to make 3 equal triangles
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$\begingroup$ is 3 equal a condition? $\endgroup$ – Sagar Chand May 29 '20 at 4:19
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1$\begingroup$ Does equal mean congruent, or just similar? $\endgroup$ – athin May 29 '20 at 12:41
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1$\begingroup$ Hm.. What's the trick here? 3D? Negative space? $\endgroup$ – Sphinxxx May 29 '20 at 15:55
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1$\begingroup$ What would be the answer?? $\endgroup$ – Always Confused May 31 '20 at 16:59
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If moving means applying force, we can bend the rule without breaking it.
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Take one match and lay it horizontally across the top two (red in picture below)
Take another match, break it into thirds, and lay two of the pieces down (two greens)
Picture (may not be to scale):
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$\begingroup$ @mimic The question said "move 2" which I interpret as "move 2 matchsticks" not "make 2 moves". $\endgroup$ – JS1 Nov 30 '20 at 19:31
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$\begingroup$ Well, okay, but "move" usually doesn't mean "break". $\endgroup$ – mimic Dec 1 '20 at 20:12
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$\begingroup$ @mimic Given the fact that no one has solved this puzzle in 6+ months, I think lateral thinking is required. $\endgroup$ – JS1 Dec 1 '20 at 21:37
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Not quite sure what the trick is, but I can at least get four triangles with three moves:
Six in four, of course, trivially follows.
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This is the only kind of arrangement I can think of:
It creates the vertices of three small isosceles triangles at A, B and C.
There are similar arrangements possible – the two matches can be moved up or down to make other shapes of congruent triangle.
answered May 28 '20 at 15:03
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1$\begingroup$ It seems like you could get four triangles with this logic. $\endgroup$ – hexomino May 28 '20 at 19:14
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$\begingroup$ @Weather Vane, apologies, but I still do not see the triangles? $\endgroup$ – Sagar Chand May 29 '20 at 4:17
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1$\begingroup$ @SagarChand after several hours no one had solved the puzzle so I posted this, and now even after a day there is no other solution that moves only two matches. Keep looking! $\endgroup$ – Weather Vane May 29 '20 at 12:19
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$\begingroup$ @WeatherVane I suspect there is no correct solution. $\endgroup$ – mimic Dec 1 '20 at 21:55
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Could not do it by moving 2 matchsticks but by moving 3 or 4 matchsticks gives me some lucrative results.
This is by 3 moves
These are by 4 moves
