Here is a table, inside there are simple operations to perform, but there are also particular numbers that don't have the same logic.
So how difficult will it be to find the last number and the pattern to solve this one?
Hope you'll enjoy this!
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Sign up to join this communityHere is a table, inside there are simple operations to perform, but there are also particular numbers that don't have the same logic.
So how difficult will it be to find the last number and the pattern to solve this one?
Hope you'll enjoy this!
105. Each diagonal cell is the multiplication entry $+25, +20, +15, +10, +5$.
Answer could be 95 or 113 or 112. Here's how: a) 95: After 29, all the numbers in that diagonal are moving like, 1st digit is next odd number and 2nd digit is obtained by subtracting the first digit number from the 2nd digit of predecessor diagonal number. So, numbers goes like, 2 9 3 6 i.e.(9-3) 5 1 i.e.(6-5) 7 4 i.e.([1]1 - 7) 9 5 i.e. ([1]4 - 9)
b) 113 or 112: Same logic as above, with a difference that 1st numbers are successive prime numbers and not odd, which will make the first number 11. For second number, there could be 02 options either treat 1st digit as 11 [eleven] or 11[one and one]. If we treat it, as 11 [eleven], no. is 11 3 i.e. ([1]4 - 11) 11 [one and one], no. is 11 2 i.e. ([1]4 - (1 + 1)) Among 113 or 112, 113 sounds more logical, cause we have taken first digit as 11 [eleven].
The question is ''105'' because ''29+7=36'' ''36+7+7+1=51'' ''51+7+7+7+2=74'' and ''74+7+7+7+7+3= 105''