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There is a 6x6 grid. Each row/column has A, B, C and D exactly once, and two blanks. Each cell may have upto one letter only. A blank is not a letter.

Hints

  • The left-most letter of row 2 is A and right-most is B
  • The left-most letter of row 3 is also A
  • The right-most letter of row 4 is B
  • The left-most letters of row 5 and 6 are both B
  • The first letter of the first column is D
  • The first letter in columns 2 and 3 is A
  • Column 2 ends with D (or 1/2 spaces after a D)
  • For column 4 and 6, the first letter is B and last is C

There exists a unique solution; I have twice-verified.

Please help out with the tags...

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  • $\begingroup$ Don't the first two conditions put the letter A in column 1 twice? (And the same with B in 2, 4, 5, and 6?) $\endgroup$
    – user20
    Mar 2, 2015 at 10:43
  • $\begingroup$ @Emrakul I think he meant it as "First letter of row..." $\endgroup$
    – Novarg
    Mar 2, 2015 at 10:46
  • $\begingroup$ @Novarg Hmm... if A is the first letter in two rows, it seems like it'd still violate the rules of the puzzle. $\endgroup$
    – user20
    Mar 2, 2015 at 10:54
  • $\begingroup$ @Emrakul by saying "First letter of row" I meant that there are no other letters before that, but there can be a blank $\endgroup$
    – Novarg
    Mar 2, 2015 at 10:56
  • $\begingroup$ @Novarg Ahh, I see. That makes sense, thanks! $\endgroup$
    – user20
    Mar 2, 2015 at 10:57

1 Answer 1

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Does this work? ;)

Oh well, this puzzle was something else. Innovative indeed and mind-boggling! Thanks!

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    $\begingroup$ These puzzles are sometimes called "easy as abc" puzzles and there are a lot of them. check this image search: google.com/search?q=EASY+AS+ABC+puzzles&tbm=isch $\endgroup$
    – Ivo
    Mar 2, 2015 at 14:07
  • $\begingroup$ Thanks, I didn't know those existed. +1 Still I'd let the 'innovative' word live in my answer, assuming the OP created it. :) $\endgroup$
    – Donbhupi
    Mar 2, 2015 at 14:10
  • $\begingroup$ @IvoBeckers Oh, ok. I had seen found one in a book, so I tweaked it a bit and posted it. Thanks for letting me know that others make them as well. $\endgroup$ Mar 2, 2015 at 18:57

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