3
$\begingroup$

I know this is a very general question, but these kinds of puzzles are the only ones I can't figure out on my own. Rubik's cube, Twiddle, 16... (the last two are in Simon Tatham's Puzzle collection.)

Is there a general thinking principle that applies to puzzles like these? If not, can you give me an example of how to arrive at the solution for any one of these puzzles? I just can't even begin to think about something with so many interconnected parts.

$\endgroup$
4

1 Answer 1

2
$\begingroup$

Permutation puzzles are puzzles in which a random permutation needs to be restored to the identity permutation by using a limited (or 'clumsy') set of moves.

For example, with the Rubik's cube, you would like to be able to swap two corners by themselves, but you can't do this directly - you can only rotate faces.

A key feature is then to find - and hopefully optimize - the solving process.

For example, consider that you are only allowed to rotate three elements of a permutation forwards, e.g. $abc\to cab\to bca\to abc$. The three elements do not need to be consecutive.

Then $1234\to4321$ can be done in four steps:

 1234
 3124
 3412
 3241
 4321

Or:

 1234
 1423
 2143
 4213
 4321

But can it be done in three moves or less? And if not, why not?

It can:

 1234
 4132
 4213
 4321

And, as the OP found, a solution in 2:

 1234
 4213
 4321

The challenge is now to find the shortest solution to reverse n numbers, but that's a different question!

My example shows how the straightforward approach is not necessarily the shortest, but the easiest to construct. So to solve a permutation puzzle, construct the 'obvious' solution first, and then try to find shortcuts.

$\endgroup$
3
  • $\begingroup$ Well, I assume that question was directed to me; getting the "1" to its position in itself takes 3 moves. So it can't be less than 3 moves. It can't be 3 moves either because "4" has to move in place as well and the first click to move "1" will not be able to move "4". I think this reasoning proves that the solution can be - at minimum - 4 moves. $\endgroup$
    – Puzzlees
    Mar 27, 2020 at 22:16
  • $\begingroup$ You can rotate 124 or 134 first (to get 4132 or 4213). @alexoland $\endgroup$
    – JMP
    Mar 28, 2020 at 3:56
  • $\begingroup$ Well then 2 moves is clearly possible: 1234 4213 4321 It can't be 1 because there is no way to move the "1" to its position in 1 move. But I don't feel like I am solving this in the proper way. I am just trying things out and stumble into a solution. Is there something else you want me to realize? $\endgroup$
    – Puzzlees
    Mar 28, 2020 at 18:28

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.