Ten pirates are sitting around a table. Each of them has an even number of coins. At order of the captain, each pirate passes half of his coins to the neighbor to the right. After that round, each pirate with an odd number of coins gets 1 coin from the captain. The captain isn't sitting at the table and has an inexhaustible amount of coins. Then this procedure is repeated again until all pirates have the same amount of coins.
It that always possible?