I found this puzzle in a VRChat world.
Its a 6 number puzzle, and I need to know the value of “? ? ? ? ? ?”.
I also need to know the number. 
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$\begingroup$ odd numbers are changing but i still cant come up with right answer $\endgroup$ – user64869 Jan 12 '20 at 15:14
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1$\begingroup$ Welcome to Puzzling.SE! Where did you get this puzzle from? For puzzles you found elsewhere, we require you to link to the original source, otherwise it could be considered plagiarism. $\endgroup$ – F1Krazy Jan 12 '20 at 15:23
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$\begingroup$ its from a vrchat world someone create to challenge people brains i dont know if i can provide a source off a game $\endgroup$ – user64869 Jan 12 '20 at 15:25
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$\begingroup$ Hmm... fair point. In that case, I personally think an edit to the question saying "I found this puzzle in a VRChat world" would be enough. $\endgroup$ – F1Krazy Jan 12 '20 at 15:27
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I would argue that this is a poorly specified puzzle (as is common with these things). @MacGyver88's solution is completely valid. But you could equally say
The last row is double the second last row and get 242424.
In fact, if you assume that this is a column-by-column operation, you could set up a system of simultaneous equations to figure out what that operation was (assuming it was linear which is not necessarily valid but we would want to start with simple assumptions):
\begin{eqnarray} 3&a &+ &b &+& c &= 2\\ 2 &a &+ 2&b &+& c &= 4\\ &a &+ 3 &b &+ &c &= 6 \end{eqnarray}
This yields a family of solutions:
\begin{eqnarray} b &=& a+2\\ c &=& -4a \end{eqnarray}
The first solution is simply the $a=0$ case. But there are infinitely many others. Here's a spreadsheet enumerating some of them. Here's a screenshot if you don't want to fiddle with the formulae:
The two "best" ones are the $a=0$ already mentioned and the $a=-1$ which yields:
"Take the first number from the second and add 4" as the rule. This gives 442200 for the question marks
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So, the solution might be
777333
Here's how I did it
Fold the first two lines down the middle
Add the numbers together
Enter the numbers in order from top to bottom on the last line
Here's what I did:
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Alternative solution
242424
X1y1z1
X2y2z2
X3y3z3
X3=(x1+x2)-(x1-x2)
Y3=(y1+y2)-(y1-y2)
Z3=(z1+z2)-(z1-z2)
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$\begingroup$ $(x_1+x_2) - (x_1-x_2) = 2 x_2$ . It just says $2\times121212 = 242424$ $\endgroup$ – Florian F Jan 18 '20 at 22:53
