4
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I sum up S4; there exists a ⵢ8

How many numbers does this strange summation encode, and what's the encoding?

Hint:

You do the hokey pokey and you turn your head around

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  • $\begingroup$ Is S4 referring to rot13(gur flzzrgevp tebhc bs qrterr sbhe be ba bs vgf vfbzbecuvfzf)? $\endgroup$ – Thomas Markov Dec 11 '19 at 17:48
  • $\begingroup$ @ThomasMarkov No, the puzzle is a lot simpler than that. $\endgroup$ – Avi Dec 11 '19 at 17:53
9
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Based on Thomas' answer and the hint on that, the answer is:

12345678

Because:

'I sum up S4' can be represented as 'I∑S4'
'There exists a ⵢ8' can be represented as '∃aⵢ8' ('a' thanks to hdsdv)
You turn your head around, as in the top half of the symbol.
'I' remains unchanged, and looks like a '1'
'∑' twists the top to look like 'Z', which also looks like '2'
'S' twists the top to looks like '3'
'4' remains unchanged
'∃' twists the top to look like a squared '5'
'a' twists the top to look like a '6'
'ⵢ' twists the top to look like '7'
'8' remains unchanged

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  • $\begingroup$ Nice, i was thinking similar train $\endgroup$ – Pogrindis Dec 12 '19 at 23:52
  • 1
    $\begingroup$ I think the missing digit is in there as well, encoded as rot13(n). $\endgroup$ – hdsdv Dec 13 '19 at 0:30
  • $\begingroup$ @hdsdv I think you are right, I was looking for that, but thought it would be a 'b'. Thanks! $\endgroup$ – Matthew Jensen Dec 13 '19 at 0:36
  • $\begingroup$ Well done, and nice explanation! $\endgroup$ – Avi Dec 13 '19 at 1:21
3
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A single number. "I∫S4;∃ⵢ8" looks like $1554.358$.

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  • $\begingroup$ You're on the right track with rot13(gheavat jbeqf vagb flzobyf, ohg na nqqvgvbany genafsbezngvba arrqf gb or cresbezrq gb erirefr ratvarre gur bevtvany ahzoref.) Also, your choice for "sum up" is incorrect. $\endgroup$ – Avi Dec 11 '19 at 22:33
2
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$I\sum S4\exists ⵢ8$ gives $1324328$

Because:

Based on the hint, the symbols that are reversed forms of numbers need to be turned around, so the $\Sigma$ is reversed to a 3, the S is reverses to a two and the ⵢ is also reversed to a 2.

So,

To answer the question, 5 of the seven digits in the "original number" (1324328) are encoded into letters and words.

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  • $\begingroup$ This is incorrect. Perhaps you should compare my hint and the original - there's a significant difference. $\endgroup$ – Avi Dec 12 '19 at 16:07

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