Can you place 42 bishops with 6 bishops for each of the 7 colors on a 10x10 grid, such that no two bishops of different colors attack each other?
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asked Nov 26, 2019 at 0:56
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3$\begingroup$ I sure hope you aren't going to do this with every possible grid size... $\endgroup$– QuintecNov 26, 2019 at 1:10
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2$\begingroup$ I think this one is too easy, finding the solution with almost no effort. $\endgroup$– Daniel MathiasNov 26, 2019 at 1:16
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1$\begingroup$ Thank you Daniel. You are right it was probably too easy. So I modified the problem. $\endgroup$– Dmitry KamenetskyNov 26, 2019 at 1:19
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1$\begingroup$ @Quintec This will be the last one I promise :P $\endgroup$– Dmitry KamenetskyNov 26, 2019 at 1:21
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1$\begingroup$ @RewanDemontay perhaps a 2x2x2x2x2x2 grid would be interesting ;) $\endgroup$– Dmitry KamenetskyNov 26, 2019 at 1:24
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1 Answer
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This was probably not the most exciting question. Anyway there are many solutions. Here are some examples:
723...5617 2.23456..1 32.......6 .3......65 .4......5. .5......4. .6.......4 .1.....7.3 171654...2 71....4327 512...3.65 1.124.7.56 21....6... .2.....673 .4........ .3......4. 37......24 7......... 6..7342.51 5673..4.15 12.3..4671 21.5346..7 .........6 35......64 .3......4. .......... 467....253 ...7..2..5 71.6..5..2 17.4..3521
Interestingly one cannot add a single other bishop of any color.
answered Dec 9, 2019 at 6:55