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Can you place 42 bishops with 6 bishops for each of the 7 colors on a 10x10 grid, such that no two bishops of different colors attack each other?

Here are some similar questions:

Peaceable Bishops on an 8x8 grid

Peaceable Bishops on an 10x10 grid

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    $\begingroup$ I sure hope you aren't going to do this with every possible grid size... $\endgroup$
    – Quintec
    Nov 26, 2019 at 1:10
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    $\begingroup$ I think this one is too easy, finding the solution with almost no effort. $\endgroup$ Nov 26, 2019 at 1:16
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    $\begingroup$ Thank you Daniel. You are right it was probably too easy. So I modified the problem. $\endgroup$ Nov 26, 2019 at 1:19
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    $\begingroup$ @Quintec This will be the last one I promise :P $\endgroup$ Nov 26, 2019 at 1:21
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    $\begingroup$ @RewanDemontay perhaps a 2x2x2x2x2x2 grid would be interesting ;) $\endgroup$ Nov 26, 2019 at 1:24

1 Answer 1

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This was probably not the most exciting question. Anyway there are many solutions. Here are some examples:

723...5617
2.23456..1
32.......6
.3......65
.4......5.
.5......4.
.6.......4
.1.....7.3
171654...2
71....4327

512...3.65
1.124.7.56
21....6...
.2.....673
.4........
.3......4.
37......24
7.........
6..7342.51
5673..4.15

12.3..4671
21.5346..7
.........6
35......64
.3......4.
..........
467....253
...7..2..5
71.6..5..2
17.4..3521

Interestingly one cannot add a single other bishop of any color.

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