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Can you place 42 bishops with 6 bishops for each of the 7 colors on a 10x10 grid, such that no two bishops of different colors attack each other?

Here are some similar questions:

Peaceable Bishops on an 8x8 grid

Peaceable Bishops on an 10x10 grid

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    $\begingroup$ I sure hope you aren't going to do this with every possible grid size... $\endgroup$ – Quintec Nov 26 '19 at 1:10
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    $\begingroup$ I think this one is too easy, finding the solution with almost no effort. $\endgroup$ – Daniel Mathias Nov 26 '19 at 1:16
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    $\begingroup$ Thank you Daniel. You are right it was probably too easy. So I modified the problem. $\endgroup$ – Dmitry Kamenetsky Nov 26 '19 at 1:19
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    $\begingroup$ @Quintec This will be the last one I promise :P $\endgroup$ – Dmitry Kamenetsky Nov 26 '19 at 1:21
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    $\begingroup$ @RewanDemontay perhaps a 2x2x2x2x2x2 grid would be interesting ;) $\endgroup$ – Dmitry Kamenetsky Nov 26 '19 at 1:24
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This was probably not the most exciting question. Anyway there are many solutions. Here are some examples:

723...5617
2.23456..1
32.......6
.3......65
.4......5.
.5......4.
.6.......4
.1.....7.3
171654...2
71....4327

512...3.65
1.124.7.56
21....6...
.2.....673
.4........
.3......4.
37......24
7.........
6..7342.51
5673..4.15

12.3..4671
21.5346..7
.........6
35......64
.3......4.
..........
467....253
...7..2..5
71.6..5..2
17.4..3521

Interestingly one cannot add a single other bishop of any color.

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