5
$\begingroup$

*) SQUARE makes 4 SQUARES. **) CUBE makes 2 SQUARES.

Add, and almost a square I am.

What am I?

$\endgroup$
  • 1
    $\begingroup$ it seems like that this puzzle comes from elsewhere. please provide the source. unattributed work may get downvoted or even closed. happy puzzling ;) $\endgroup$ – Omega Krypton Nov 20 at 11:51
  • 2
    $\begingroup$ No this is honestly my own creation. I might have been influenced by naming it "what am I". But that's it. $\endgroup$ – Prim3numbah Nov 20 at 11:57
  • 1
    $\begingroup$ Ok then, thanks for clarifying! $\endgroup$ – Omega Krypton Nov 20 at 12:01
3
$\begingroup$

You are 24 because ii) 2^3=2^2+2^2 and i) 4^2=2^2+2^2+2^2+2^2 16+8=24 which is -1 of 25 and so nearly 5^2

$\endgroup$
  • 1
    $\begingroup$ But 4^3=64 while 5^2 (25) + 7^2 (49) = 74, so the two are not equal...? Also, how would that part relate to the overall answer being 145? $\endgroup$ – Stiv Nov 20 at 18:25
  • $\begingroup$ Oops, my mental math skills suck $\endgroup$ – Deepthinker101 Nov 20 at 18:34
  • $\begingroup$ Changed it I think my math is cool now $\endgroup$ – Deepthinker101 Nov 20 at 18:39
0
$\begingroup$

You are

2

Your square

is 4, $4*1^2$

Your cube

is 8, $2*2^2$

$\endgroup$
  • $\begingroup$ I feel like there must be something else to it. This same trick works if you replace 2 with any 2n^2. Also, the last line doesn't seem to fit. $\endgroup$ – hexomino Nov 20 at 12:48
  • $\begingroup$ I'm thinking that '*' and ')' are placeholders for specific digits. However, the obvious choice (8 and 0 - their keyboard shift-equivalents) don't work out. A scan of all 4-digit squares for numbers where each digit is a square number also leads nowhere... $\endgroup$ – Stiv Nov 20 at 14:50

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