Four hand tiled squares demonstrating a Pythagorean Quadruple

$$6\times6 + 6\times6 + 7\times7 = 11\times11$$

Using the pieces shown in the $$11\times11$$ square:

The objective:

1. Arrange the pink pieces (four enneominoes) into a $$6\times6$$

2. Arrange the blue pieces (six hexominoes) into a $$6\times6$$

3. Arrange the orange pieces (seven heptominoes) into a $$7\times7$$

4. Arrange all 17 pieces into a $$11\times11$$ but with no like colours touching, even at a corner.

All four tilings are unique. Hand tiling puzzle please, a computer will just spoil it for you. Flipping pieces is allowed.

• can the tiles be flipped? thanks Oct 15 '19 at 6:55
• Are we certain the third task is possible? I have been trying off and on for a while and am getting terribly close, but never exact. Oct 15 '19 at 12:36
• Yes flipping of pieces is allowed. Added to puzzle statement. Oct 15 '19 at 13:36

Sooo much NSFW! But thanks anyway :)

Task 4 - not solved yet.

• Beautifully illustrated! Go for the last one! +1
– Stiv
Oct 15 '19 at 16:14

Like @Omega Krypton I have solved one part, Task 2: