Demonstrating the Pythagorean Quadruple
$6\times6 + 6\times6 + 7\times7 = 11\times11$
Using the pieces shown in the $11\times11$ square:
Arrange the pink pieces (four enneominoes) into a $6\times6$
Arrange the blue pieces (six hexominoes) into a $6\times6$
Arrange the orange pieces (seven heptominoes) into a $7\times7$
Arrange all 17 pieces into a $11\times11$ but with no like colours touching, even at a corner.
All four tilings are unique. Hand tiling puzzle please, a computer will just spoil it for you. Flipping pieces is allowed.