-3
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How do you make 29 with only using the numbers 1 2 3 4? I have tried a lot of solutions and please remember that you can't use the number 5

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closed as too broad by Rand al'Thor, Arnaud Mortier, JMP, Bass, Mariia Mykhailova Sep 22 at 16:28

Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

  • $\begingroup$ What operations are allowed to be used? How many times can each digit $1,2,3,4$ be used? Must they all be used? Is concatenation (e.g. $21,13$) allowed? I'm voting to close as "too broad" until more detail of the rules is provided. $\endgroup$ – Rand al'Thor Sep 22 at 12:45
  • $\begingroup$ It says numbers, not digits. Each number once goes without saying. But the list of valid operations is clearly missing. $\endgroup$ – Florian F Sep 22 at 14:18
2
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Here's several ways:

$31-\frac42$
$4!+3!-2+1$
$3^{2+1}+\sqrt{4}$
$2^{4+1}-3$
$42-13$

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One of the ways could be :-

$2^2+3^2+4^{3-1}$

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  • $\begingroup$ It is likely that each number should appear only once, otherwise there are a lot of very obvious answers. $\endgroup$ – Arnaud Mortier Sep 22 at 12:47
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    $\begingroup$ @ArnaudMortier That’s more a fault of the question than of the answer, though. $\endgroup$ – Lawrence Sep 23 at 0:31

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