So, we all know the famous 12 balls 1 scale riddle. It has been here repeated many times, however, the provided solutions always start with splitting the twelve balls into three groups of four. This made me wonder whether it would also be possible to solve the riddle in another starting combination, e.g. four groups of three.
Just in case someone doesn't know the riddle, let me quickly reiterate:
You are given twelve balls and a scale. Eleven of the balls weigh exactly the same, but one of them weighs slightly more or less (you don't know which one of these). You are allowed to use up to three weighings on the scale to determine which one of the balls is different.