In trying to develop and perfect my strategies, I've been playing 2048-undo.

This is what I got myself into:

2048 board with 4096 on top right and tiles 2048, 1024, 512, 2x256, 128, 64, 32, 8, 4, 3x2 and an inconveniently-placed 4.

Since this is not an uncommon situation and I still don't know how to properly get out of it, I figured I'd ask here.

If at all possible, what I want the most is to merge my two 256 tiles which in turn would be merged with the 512 tile and then merge with 1024, 2048 and then it should be easy enough to merge the two 4096 tiles.

But the two 256 tiles are separated by a 512 tile, and the truth is, I still haven't managed to learn how to merge two tiles when there is one in between.

Can it be accomplished? What does the general logic look like?

(please assume this is the traditional 2048 game, made by Gabriele Cirulli with inspiration from other games - see page - and not the undo version).

  • $\begingroup$ I think you should make a new 128 with the 2s, 4, 8, 32, and 64 and merge it with the other 128 because if one is in between, I don't see them getting together especially with this much of a cramped board. I think you should make more space available first. $\endgroup$
    – Duck
    Aug 2 '19 at 3:27
  • 1
    $\begingroup$ In general, you don't get to take pieces out from in between: playing a "left" at any point would mess your big tile order. (That's to say, the 4 under the 4096 is probably going to be a problem, and it probably got there because you played a left at some point.) If you absolutely can't avoid having a smaller tile in your big tile chain, you'll want to grow that one up until it becomes big enough to be in that spot. $\endgroup$
    – Bass
    Aug 2 '19 at 8:04
  • $\begingroup$ Given that the next generated tile can be 2 or 4 and can be generated in any space, how would one solve a problem like this? $\endgroup$ Aug 6 '19 at 2:43

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