Bob puts the card in an order, Ann can always win the game by +1.
let's think the game with 1,3,4,5 where the sum is not even.
so whatever Bob can arrange these cards in the best case scenario,
Ann will win by +1, $4,1,5,3$, because Ann needs any two cards without 1 only and since Ann starts the game she can arrange it whatever the original arrangement. Ann will take $4 + 5$ or $3+4$ since Ann has advantage choosing at the end between two numbers.
Let's make it more complex;
the game with 0,1,2,3,4,5, and the sum is not even again, so only one draw is possible so, Ann will win the game if she takes 8 or more points with 3 cards. and after choosing her first two cards, she can choose between two cards and take the biggest at worst before ending the game so Ann will have advantage at least +1 at the end. Moreover, Ann needs to arrange her strategy by summing every number by passing the number next to it in the list, such as let's say order is $1,4,2,5,3,0$, so let's take sum from the beginning by passing one number at a time, so the sum becomes $1+2+3$, so we should not start from there, start from the other end to guarantee to win the game.
so even it is 0 to 100, Ann will
win the game if the sum is odd with the methodology above.