Xit's time for round two!

Given that:

-Black has 6 pawns and a king

-White ehas three pieces of any kind you to deduce the identity of and a king


-A nlegal position in which both sides help to give a legal sequence of 13 mutual checks

Positional ovariations are allowed. To my knowledge, there is really only one way in which this idea can be constructed. I accept alternate answers.

If you ohave questions, feel free to ask in the comments section below!

Good rluck!

There is a slight shortcut for this puzzle if you can figure it out...

  • $\begingroup$ To clarify: W has three pieces of the same kind that we have to identify, or W has three pieces which might all be of different kinds that we have to identify? $\endgroup$ – Gareth McCaughan Jul 14 '19 at 20:04
  • $\begingroup$ It's the latter option. $\endgroup$ – Rewan Demontay Jul 14 '19 at 20:09

My position has a fourteenth check too, but that's probably ok. :-)

enter image description here
[FEN "8/8/8/8/8/4K3/2pppppp/RR4Nk w - -"]

These are the moves:

 1. Nh3+  d1=N+
 2. Rxd1+ cxd1=N+
 3. Rxd1+ e1=R+
 4. Rxe1+ f1=N+
 5. Rxf1+ g1=B+
 6. Rxg1+ hxg1=B+
 7. Nf2+  Bxf2+

And here's the whole solution uploaded to Lichess.

EDIT: Looks like 15 is also doable:

enter image description here

The final check feels like such a waste of a piece though; the first fourteen checks are possible with white having only two pieces and a king:

[FEN "8/8/6Q1/8/5R2/5p2/ppp1p1p1/R3K1k1 w - -"]

 1. Qb6+   f2+
 2. Kd2+   b1=N+ 
 3. Qxb1+  axb1=N+ 
 4. Rxb1+  c1=B+
 5. Rxc1+  e1=B+ 
 6. Rxe1+  f1=N+ 
 7. Rexf1+ gxf1=N+ 
 8. Rxf1+

Again, here's the Lichess link.

  • $\begingroup$ Incredible! Thank goodness I checked back. I was wasting so much time not considering promotions! Would love to know your thought process? Had you just seen this kind of pattern before? $\endgroup$ – Parseltongue Jul 14 '19 at 21:35
  • $\begingroup$ +1. But it's probably not the solution intended by the asker, since it doesn't explain the sequence of extra letters in the question. $\endgroup$ – msh210 Jul 14 '19 at 21:37
  • $\begingroup$ nice. I think you could substitute queens for one or both of the rooks, too. $\endgroup$ – SteveV Jul 14 '19 at 21:40
  • $\begingroup$ @mah210 It is not required to solve for the extra letters. Those are a bonus of sorts if you can figure it out. $\endgroup$ – Rewan Demontay Jul 14 '19 at 21:40
  • 2
    $\begingroup$ @RewanDemontay TWO more :-) $\endgroup$ – Bass Jul 14 '19 at 22:20

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