I am fully hopeful that you can crack this puzzle.
You need to answer with an explanation.
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In the first row, add $2$ to the $1$ and multiply with the $3$ to get $9$. In the second row, double the $4$ and multiply with the $3$ to get $24$. In the third row, we do both - add $2$ to the $5$ and double the $2$, then multiply to get $28$. If you now observe the pattern of bold/normal font for the first two columns, it repeats on the fourth row, so we add $2$ to the $4$ and multiply with the $5$ to get $30$.
Answer: Idea similar JonMarkPerry, but slightly different, my guess:
1)BOLD NUMBER = BOLD NUMBER +2
2) right number is multiple of first two in a row multiply by number of simple divisors of each number(beginning one, not+2) different from it (EX for 3 is 1, 4 is 2 and 1, for 6 is 3 and 2 and 1 and so on)
3)right number is not bold only if first two are not bold
4) using those rules we get (1+2)*3*1*1=9(bold) 3*4*1*2=24(not bold) (2+2)*(5+2)*1*1=28(bold) so (4+2)*5*2*1=60(bold)
My solution is...
$l = left$
$r = right$
$2l + r = 15$
$-l + r = 4 | +l$
$r = 4 + l$
$6l = 15 |:6$
$l = 2.5$
$r = 6.5$
So the next number is:
$2l + 28 = 33$
(I thought that the bold numbers doesn't matter)