# Holy Alphabet Arithmetic

$$Given$$:

$$A$$+$$B$$+$$C$$=3

$$B$$+$$C$$+$$D$$=3

$$C$$+$$D$$+$$E$$=1

$$D$$+$$E$$+$$F$$=1

What is

$$E$$+$$F$$+$$G$$=?

$$0$$
In particular $$A$$ has $$1$$, $$B$$ has $$2$$ and $$D$$ had $$1$$ but $$C, E, F$$ and $$G$$ have none.