4
$\begingroup$

Rules:

  1. All 3 digits — $3$, $3$, and $5$ — must be used once each in any order. You can concatenate these digits to create multi-digit numbers (i.e. $33$).
  2. You can use the factorial operation ($n!$), the subfactorial operation ($!n$) and the double factorial operation ($n!!$) (i.e. $3!=6$, $!5=44$, $(3!)!!=48$). However, extended multi-factorials ($n!!!...$) cannot be used.
  3. $+$, $-$, $\times$, $/$,$()$, $\hat{}$ can be used for functions.
  4. You cannot use: round, floor, ceiling, truncate function or functions such as sin, cos, log.
$\endgroup$
4
  • 1
    $\begingroup$ Is sqrt allowed? Also, what about repeating decimal operator? Also, what about decimal points, such as ".3"? $\endgroup$
    – JS1
    Jul 2 '19 at 23:16
  • 1
    $\begingroup$ Do you mean 67 and 97, or 67 or 97? If you mean or, consider giving @malioboro's answer a checkmark. $\endgroup$
    – Duck
    Jul 2 '19 at 23:17
  • $\begingroup$ @Duck that answer uses concatenation after modifying the numbers, which is not the same thing as making a multi-digit number out of the original digits. $\endgroup$
    – Bass
    Jul 3 '19 at 6:34
  • $\begingroup$ Same problem occurred here with my answer: puzzling.stackexchange.com/questions/84834/… $\endgroup$
    – Duck
    Jul 3 '19 at 15:30
7
$\begingroup$

I think this works for 97:

$!(3!)-5!-(3!)!!=97$

$\endgroup$
3
  • $\begingroup$ @Neil W is there any way to combine our answers? $\endgroup$
    – sunfishho
    Jul 4 '19 at 7:51
  • $\begingroup$ Nice find! For those wondering, this simplifies to $265 - 120 - 48 = 97$ $\endgroup$
    – JS1
    Jul 4 '19 at 9:03
  • $\begingroup$ I don't even know how lucky I was to find this @JS1 $\endgroup$
    – sunfishho
    Jul 4 '19 at 15:39
9
$\begingroup$

With a decimal point

$67 = .5^{-(3!)}+3$

$\endgroup$
1
  • 2
    $\begingroup$ I like this much better than the one with concatenation, because with concatenation it is easy to make both 67 and 97. Example: $5! - ((!3) || 3) = 120 - (2 || 3) = 120 - 23 = 97$ $\endgroup$
    – JS1
    Jul 3 '19 at 17:08
4
$\begingroup$

( Partial answer)

for 67:

$3! \Vert (!3+5) $

$\endgroup$
7
  • $\begingroup$ Wait, that's not partial, it says 67 or 97, not both. +1 :) $\endgroup$
    – Duck
    Jul 2 '19 at 22:05
  • $\begingroup$ wait, that is a concatenation, isnt it? is that allowed?? $\endgroup$ Jul 2 '19 at 23:31
  • $\begingroup$ Doesn't say concatenation isn't allowed. $\endgroup$
    – Duck
    Jul 2 '19 at 23:36
  • $\begingroup$ @OmegaKrypton I'm not pretty sure, actually. I think the first rule is said that we allowed doing something like concatenation $\endgroup$
    – malioboro
    Jul 3 '19 at 0:07
  • $\begingroup$ I think that is only applicable for the original numbers? $\endgroup$ Jul 3 '19 at 0:32

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.