-6
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In their own Circle.

Such that the arrows point to successive numbers . Start with 1 and end with 9. There might be more arrows than necessary.

Find the solution with least number of arrows ignored.

enter image description here

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  • $\begingroup$ Are the 'redundant' arrows on purpose or 'there might be' there because of a potential error? $\endgroup$ – rhsquared Jun 23 at 16:11
  • $\begingroup$ There are there to produce right path..there might be more arrows necessary..you don’t have to use them $\endgroup$ – Uvc Jun 23 at 16:13
  • $\begingroup$ Why negative vote? Is it easy..then you should post the solution..I am trying to give puzzles of varying genres and varying degrees of difficulties so that everybody can enjoy....Ihave always taken valid honest feedback and benefitted from it $\endgroup$ – Uvc Jun 23 at 16:39
  • 1
    $\begingroup$ I didn't downvote but I think it's very unclear what's being asked here. It seems that some of the arrows are false (rather than just unnecessary) and part of the puzzle involves removing or ignoring them. Is that right? $\endgroup$ – hexomino Jun 23 at 17:15
  • $\begingroup$ In some of my puzzles, when there was some missing info or need clarification, I have responded as promptly as I can to correct the situation. I am not here to confuse the solver..sometimes there is extra info which can be discarded if it is not part of the logic..sometimes what seems missing initially comes out after right reasoning..in this case I have put it succinctly as what is needed..appreciate the feedback $\endgroup$ – Uvc Jun 23 at 17:54
2
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I get

7 8 9
6 4 1
5 2 3
Note top right must be 9 and the left side must be sequential going upwards. From there, I did some guess-and-check, but it's entirely possible to reason that the center must come before the left column, and the bottom right before the center, and the bottom center before the bottom right, and the right center before the bottom center, and the right center must be the first which solves 1-7 and 9 which gives you the top center as 8.

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  • $\begingroup$ Got it right... $\endgroup$ – Uvc Jun 23 at 17:48

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