11111111, 333333, 5555, 77, ?

Find the most complete and simplest solution that fits.

  • $\begingroup$ Whoever VTC'd did so for an incorrect reason. In fact, I don't really see a reason to close this. $\endgroup$ – greenturtle3141 Jun 5 '19 at 0:32

The most complete and simple solution I can think of


the empty space above, represents
$ \mathbb{NOTHING} $

Factorising the numbers does not reveal any pattern so
I went with the sequence of digits. The next one after $1, 3, 5, 7$ is $9$.
The number of occurrences of each digit after $8, 6, 4, 2$ is $0$.
So there are no nines.
That is not zero, but an empty space — nothing.

  • $\begingroup$ I would be surprised if there were a simpler solution than this. $\endgroup$ – hexomino Jun 5 '19 at 9:17
  • $\begingroup$ Empty nines, or empty anything, is there a difference? $\endgroup$ – z100 Jun 5 '19 at 22:29
  • $\begingroup$ @z100 oh yes. What is unsaid, can be as revealing as what is said. Consider too, that the absence of a winning lottery ticket is quite different from the absense of a losing lottery ticket. $\endgroup$ – Weather Vane Jun 5 '19 at 22:50

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