In this puzzle you need to obtain the highest score with the following rules
1) choose two digits from 1, 2, 3, 4, 5, 6, 7, 8 and 9. These digits are represented by two letters, let us say $T$ and $M$. You are also given the digit 0.
2) make up an equation using all three of your digits, $T$, 0 and $M$, once. The numerical result of the equation should be a three digit number which can be $TM0$, $T0M$, $MT0$, $M0T$, $0MT$ and $0TM$. You may not concatenate digits, but you may use as many as the following symbols as you would like $+$, $-$, $\div$, $\times$, !, $\sqrt{}$, (, ). Note that multiple ! symbols are considered each to be factorial functions. See the note below.
3) Your score is your three digit number divided by the sum of your digits. So for example if you start with 0, 2, 4 then your equation could be
$$(0*2)+4!=024$$
which would score $024 \div (2+4+0) = 24\div 6 = 4$
This question was inspired by this question
Note that: $4!! = (4!)! = 24!$ this is allowed. Double, triple etc. factorials are not allowed; $4!! \ne 4 \times 2$