# Make a formula to get the highest score

In this puzzle you need to obtain the highest score with the following rules

1) choose two digits from 1, 2, 3, 4, 5, 6, 7, 8 and 9. These digits are represented by two letters, let us say $$T$$ and $$M$$. You are also given the digit 0.

2) make up an equation using all three of your digits, $$T$$, 0 and $$M$$, once. The numerical result of the equation should be a three digit number which can be $$TM0$$, $$T0M$$, $$MT0$$, $$M0T$$, $$0MT$$ and $$0TM$$. You may not concatenate digits, but you may use as many as the following symbols as you would like $$+$$, $$-$$, $$\div$$, $$\times$$, !, $$\sqrt{}$$, (, ). Note that multiple ! symbols are considered each to be factorial functions. See the note below.

$$(0*2)+4!=024$$

which would score $$024 \div (2+4+0) = 24\div 6 = 4$$

This question was inspired by this question

Note that: $$4!! = (4!)! = 24!$$ this is allowed. Double, triple etc. factorials are not allowed; $$4!! \ne 4 \times 2$$

• Is the use of the decimal point allowed? – hexomino May 29 '19 at 23:29
• @hexomino no, but i will of course upvote a creative answer using one.... – tom May 30 '19 at 3:17
• I'm voting to close this question because it seems too open-ended to have a unique best answer. – Rand al'Thor May 30 '19 at 17:20
• @Randal'Thor I appreciate your point, but It seems to me that the answer given is fine and explains things well - sorry if I have taken too long to accept the answer. – tom May 30 '19 at 22:38

$$(7-2+0!)!=6!=720$$.
$$410,\;510,\;610,\;710,\;810,\;910,\;820$$ and $$920$$