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This question already has an answer here:

Using standard mathematical symbols, (i.e. no other letters or numbers), make the following true:

0 0 0 = 6
1 1 1 = 6
2 2 2 = 6
3 3 3 = 6
4 4 4 = 6
5 5 5 = 6
6 6 6 = 6
7 7 7 = 6
8 8 8 = 6
9 9 9 = 6

As a freebie, I will give the easiest away, 2 + 2 + 2 = 6

All numbers are base 10...

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marked as duplicate by Glorfindel, Omega Krypton, elias, athin, gabbo1092 May 24 at 13:05

This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.

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    $\begingroup$ Possible duplicate of 6, the magic number - I should've known it was asked before. $\endgroup$ – Glorfindel May 24 at 11:25
  • $\begingroup$ Drat, I was completely unaware... I tried every possible combination of searches to verify the possibility of a duplicate and came up with nothing... @Glorfindel I've given you a vote up to help ease the pain... $\endgroup$ – Eliseo d'Annunzio May 27 at 1:27
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Here you go:

(0! + 0! + 0!)! = 6
(1 + 1 + 1)! = 6
2^2 + 2 = 6
3 * 3 - 3 = 6
√4 + √4 + √4 = 6
5 + 5 / 5 = 6
6 + 6 - 6 = 6
7 - 7 / 7 = 6
8 - √(√(8 + 8)) = 6
√9 * √9 - √9 = 6

(for those of you unfamiliar with the !, it's the factorial)

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  • $\begingroup$ Definitely well thought out. I pretty much had the same answers when I was first presented with this puzzle a while back. Well done. $\endgroup$ – Eliseo d'Annunzio May 24 at 11:24
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Some variations:

(0! + 0! + 0!)! = 6
(1 + 1 + 1)! = 6
2 + 2 + 2 = 6
3! - 3! + 3!= 6
√4 + √4 + √4 = 6
5 / 5 + 5 = 6
6 + 6 - 6 = 6
7 - 7 / 7 = 6
8 - √(√(8 + 8)) = 6
√9 * √9 - √9 = 6

And an other minimalist solution (for computer folks)

0 + 0 + 0 != 6
1 + 1 + 1 != 6
2 + 2 - 2 != 6
3 + 3 + 3 != 6
4 + 4 + 4 != 6
5 + 5 + 5 != 6
6 + 6 + 6 != 6
7 + 7 + 7 != 6
8 + 8 + 8 != 6
9 + 9 + 9 != 6

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  • 2
    $\begingroup$ If you add two spaces after each spoilered line, the formatting will work as intended. $\endgroup$ – Glorfindel May 24 at 11:25
  • $\begingroup$ I hadn't considered 3! - 3! + 3!, nice variation! $\endgroup$ – Eliseo d'Annunzio May 24 at 11:26
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    $\begingroup$ ok thx ! neewbee here:) $\endgroup$ – Synn May 24 at 11:26

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