5
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Here’s a toughie for you-and no computers allowed!

I have created this unique chess puzzle which white mates black in many different ways, all in 5 moves, no matter what black does. Options do exist for both sides.

Basically, black is trying to prolong their life as much as possible. But no matter what move they make (not like there’s a ton if options after the first 2 moves), they shall always be mated in 5 moves.

And yes, the position is legal.

EDIT: It’s come to my attention that there is much more than 9 mates in one. In this light, just find as as you can.

White To Play And Checkmate Black In 5 Moves In Many Different Ways

enter image description here

Good luck solving!

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3
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Adding another:

1. a8=N+ Qxa8
2. Kxa8 Ba6
3. Qb8 Kb5
4. Ka7 b6
5. Qxb6#

2nd one is:

1. a8=N+ Qxa8
2. Kxa8 Ba6
3. Qb8 Kb5
4. c8=N b6
5. Qxb6#

Further adding:

I think you can do a8= Q or R for the first move and still mate in 5. So, that must be another 8 such mates from the ones we have achieved with a Knight promotion.

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  • $\begingroup$ Yes, a8=R and a8=Q are different lines as well. $\endgroup$ – Rewan Demontay May 22 at 15:05
  • $\begingroup$ I don't think a8=R works because black can play Qa7+. $\endgroup$ – jafe May 22 at 16:38
  • $\begingroup$ Yes it does work. Black’s best move would be to take it anyhow. $\endgroup$ – Rewan Demontay May 22 at 17:21
  • $\begingroup$ Remember, black is trying to survive as long as they can, perhaps hoping for a stalemate as any normal player would. Qa7+ after a8=R leads to a mate in 4, not a mate in 5. $\endgroup$ – Rewan Demontay May 22 at 18:47
4
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1. a8=N+ Qxa8+
2. Kxa8 Ba6 (Ka6 Qxb7#)
3. Qd8 Kb5
4. c8=N b6
5. Qxb6#

3... Bb5
4. c8=N+ Ka6
5. Qb6#

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  • $\begingroup$ There's a pawn on c7 after the 2nd move, no? How do you get 3. Qc7? $\endgroup$ – Sid May 22 at 14:51
  • $\begingroup$ There is. You are correct. Different promotions count as different solutions. I’m struggling to come up with a number for all of the possible mates in five that exist here. There is a pawn on c7. $\endgroup$ – Rewan Demontay May 22 at 14:52
  • $\begingroup$ @Sid D'oh, you're right. That didn't work. $\endgroup$ – jafe May 22 at 14:53
  • $\begingroup$ There actually exists a mate in 4 if black makes a certain move in a certain line. $\endgroup$ – Rewan Demontay May 22 at 14:55
  • $\begingroup$ Mate in 2 as well. $\endgroup$ – jafe May 22 at 15:04
1
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Now that an answer has arisen, here my formal solution of all 39 different mates in five. You weren’t expected to find them all. The = signs indicate the type of promotion made by the pawn promotion on white’s first move. The annotations Qb8, Qd8, Qd7, and Kb8 that are by themselves indicate white’s third key move as a manner of organization.

Dang spoiler tag won’t work for me!


 Qd8
 
 1. a8=R Qxa8+ 2. Kxa8 Ba6 3. Qd8 Bb5 4. c8=N+ Ka6 5. Qb6#
 1. a8=R Qxa8+ 2. Kxa8 Ba6 3. Qd8 Bb5 4. c8=Q+ Ka6 5. Qxb7#
 1. a8=R Qxa8+ 2. Kxa8 Ba6 3. Qd8 Bb5 4. c8=B+ Ka6 5. Bxb7#
 1. a8=R Qxa8+ 2. Kxa8 Ba6 3. Qd8 Kb5 4. c8=N b6 5. Na7#
 1. a8=R Qxa8+ 2. Kxa8 Ba6 3. Qd8 Kb5 4. c8=N b6 5. Nd6#
 1. a8=R Qxa8+ 2. Kxa8 Ba6 3. Qd8 Kb5 4. c8=N b6 5. Qxb6#
 
 =Q
 
 1. a8=Q Qxa8+ 2. Kxa8 Ba6 3. Qd8 Bb5 4. c8=N+ Ka6 5. Qb6#
 1. a8=Q Qxa8+ 2. Kxa8 Ba6 3. Qd8 Bb5 4. c8=Q+ Ka6 5. Qxb7#
 1. a8=Q Qxa8+ 2. Kxa8 Ba6 3. Qd8 Bb5 4. c8=B+ Ka6 5. Bxb7#
 1. a8=Q Qxa8+ 2. Kxa8 Ba6 3. Qd8 Kb5 4. c8=N b6 5. Na7#
 1. a8=Q Qxa8+ 2. Kxa8 Ba6 3. Qd8 Kb5 4. c8=N b6 5. Nd6#
 1. a8=Q Qxa8+ 2. Kxa8 Ba6 3. Qd8 Kb5 4. c8=N b6 5. Qxb6#
 
 =N
 
 1. a8=N+ Qxa8+ 2. Kxa8 Ba6 3. Qd8 Bb5 4. c8=N+ Ka6 5. Qb6#
 1. a8=N+ Qxa8+ 2. Kxa8 Ba6 3. Qd8 Bb5 4. c8=Q+ Ka6 5. Qxb7#
 1. a8=N+ Qxa8+ 2. Kxa8 Ba6 3. Qd8 Bb5 4. c8=B+ Ka6 5. Bxb7#
 1. a8=N+ Qxa8+ 2. Kxa8 Ba6 3. Qd8 Kb5 4. c8=N b6 5. Na7#
 1. a8=N+ Qxa8+ 2. Kxa8 Ba6 3. Qd8 Kb5 4. c8=N b6 5. Nd6#
 1. a8=N+ Qxa8+ 2. Kxa8 Ba6 3. Qd8 Kb5 4. c8=N b6 5. Qxb6#
 
 Qd7
 
 =Q
 
 1. a8=Q Qxa8+ 2. Kxa8 Ba6 3. Qd7 Kb5 4. c8=N b6 5. Na7#
 1. a8=Q Qxa8+ 2. Kxa8 Ba6 3. Qd7 Kb5 4. c8=N b6 5. Nd6#
 
 =R
 
 1. a8=R Qxa8+ 2. Kxa8 Ba6 3. Qd7 Kb5 4. c8=N b6 5. Na7#
 1. a8=R Qxa8+ 2. Kxa8 Ba6 3. Qd7 Kb5 4. c8=N b6 5. Nd6#
 
 =N
 
 1. a8=N+ Qxa8+ 2. Kxa8 Ba6 3. Qd7 Kb5 4. c8=N b6 5. Nd6#
 1. a8=N+ Qxa8+ 2. Kxa8 Ba6 3. Qd7 Kb5 4. c8=N b6 5. Na7#
 
 Kb8
 
 =R
 
 1. a8=R Qxa8+ 2. Kxa8 Ba6 3. Kb8 Kb5 4. Ka7 b6 5. Qxa6#
 
 =Q
 
 1. a8=Q Qxa8+ 2. Kxa8 Ba6 3. Kb8 Kb5 4. Ka7 b6 5. Qxa6#
 
 =N
 
 1. a8=N+ Qxa8+ 2. Kxa8 Ba6 3. Kb8 Kb5 4. Ka7 b6 5. Qxa6#
 
 Qb8
 
 =Q
 
 1. a8=Q Qxa8+ 2. Kxa8 Ba6 3. Qb8 Kb5 4. Ka7 b6 5. Qxb6#
 1. a8=Q Qxa8+ 2. Kxa8 Ba6 3. Qb8 Kb5 4. c8=N b6 5. Na7#
 1. a8=Q Qxa8+ 2. Kxa8 Ba6 3. Qb8 Kb5 4. c8=N b6 5. Nd6#
 1. a8=Q Qxa8+ 2. Kxa8 Ba6 3. Qb8 Kb5 4. c8=N b6 5. Qxb6#
 
 =R
 
 1. a8=R Qxa8+ 2. Kxa8 Ba6 3. Qb8 Kb5 4. Ka7 b6 5. Qxb6#
 1. a8=R Qxa8+ 2. Kxa8 Ba6 3. Qb8 Kb5 4. c8=N b6 5. Na7#
 1. a8=R Qxa8+ 2. Kxa8 Ba6 3. Qb8 Kb5 4. c8=N b6 5. Nd6#
 1. a8=R Qxa8+ 2. Kxa8 Ba6 3. Qb8 Kb5 4. c8=N b6 5. Qxb6#
 
 =N
 
 1. a8=N+ Qxa8+ 2. Kxa8 Ba6 3. Qb8 Kb5 4. Ka7 b6 5. Qxb6#
 1. a8=N+ Qxa8+ 2. Kxa8 Ba6 3. Qb8 Kb5 4. c8=N b6 5. Na7#
 1. a8=N+ Qxa8+ 2. Kxa8 Ba6 3. Qb8 Kb5 4. c8=N b6 5. Nd6#
 1. a8=N+ Qxa8+ 2. Kxa8 Ba6 3. Qb8 Kb5 4. c8=N b6 5. Qxb6#
 

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  • $\begingroup$ Suggested an edit. Now the spoilers should work as expected. $\endgroup$ – trolley813 May 24 at 6:32
  • $\begingroup$ Thank you my friend! $\endgroup$ – Rewan Demontay May 24 at 12:51

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