Can you arrange a standard set of $28$ dominoes into a rectangle of $7\times8$, where each of the 8 rows sum to $21$ and each of the 7 columns sum to $24$?

double 6 dominoes

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Or, alternatively, pack the dominoes into their $7\times4\times2$ box, with equal rows and stacks.


1 Answer 1


This is a well known problem which has been solved. One of the solutions is described in the following paper by Michael Springfield and Wayne Goddard:


Here is the domino arrangement from this paper (it is 7x8, rotate it to get 8x7):

enter image description here


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