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Can you arrange a standard set of $28$ dominoes into a rectangle of $7\times8$, where each of the 8 rows sum to $21$ and each of the 7 columns sum to $24$?

double 6 dominoes

Image from WikiPedia.

The 'twistier' the better!

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    $\begingroup$ This is a well known problem which has been solved. One of the solutions is described in the following paper by Michael Springfield and Wayne Goddard: pdfs.semanticscholar.org/6923/… $\endgroup$ – ppgdev May 17 at 3:31

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