Find this unique composite cat given the information in this title.


The answer is



$\frac{3!}{4} = \frac{6}{4} = 1 + \frac{1}{2}$ leaves a remainder

Hint from question

cat - may be four legs


2 is the only even prime number. Before 4 , 2 occurs only once and 4 is a multiple of 2. And 3! = 6 = 3.2.1 has only one 2, hence it leaves a remainder. $$$$ Whereas for other composite numbers say, $n$, $(n-1)!$ has all the factors of $n$, and thus doesn't leave a remainder.

  • $\begingroup$ I mean, rot13(guerr yrnirf n erznvaqre jura qvivqvat gjb snpgbevny)....? $\endgroup$ – El-Guest May 15 '19 at 19:29
  • $\begingroup$ @El-Guest "Composite" cat. $\endgroup$ – hexomino May 15 '19 at 21:41
  • 2
    $\begingroup$ @hexomino by now you should know I don’t know how to read $\endgroup$ – El-Guest May 15 '19 at 21:42

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