1
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Find GC ...it is a concatenated number

Given:

N + U + M + B + E + R = GC

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5
  • $\begingroup$ Unique solution $\endgroup$
    – Uvc
    May 15 '19 at 8:42
  • 1
    $\begingroup$ why use the letters G and C in particular? $\endgroup$
    – JMP
    May 15 '19 at 8:45
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    $\begingroup$ but it hasn't got a unique solution $\endgroup$
    – JMP
    May 15 '19 at 8:49
  • $\begingroup$ tkcs-collins.com/truman/alphamet/alpha_solve.shtml you may use this for alphametric. $\endgroup$
    – Oray
    May 15 '19 at 8:58
  • $\begingroup$ Cryptography tag must be included for unique solution..please do not remove the tag $\endgroup$
    – Uvc
    May 15 '19 at 8:59
3
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This alphametic has numerous solutions. The couple I've found so far are

$1 + 3 + 4 + 5 + 6 + 8 = 27$
$1 + 4 + 5 + 6 + 7 + 9 = 32$

All other permutations of $N, U, M, B, E, R$ also work, as addition is commutative.


Edit:

Assume A1Z26.

$14 + 21 + 13 + 2 + 5 + 18 = 73$

This is a unique solution, given these constraints and the new tag.

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4
  • $\begingroup$ See the tags..... $\endgroup$
    – Uvc
    May 15 '19 at 8:52
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    $\begingroup$ Which tags in particular? $\endgroup$
    – Aranlyde
    May 15 '19 at 8:53
  • $\begingroup$ Unfortunately, people have been editing tags without understanding the question. Original tags say only include cryptography $\endgroup$
    – Uvc
    May 15 '19 at 9:08
  • $\begingroup$ Updated to add a cryptographic solution. $\endgroup$
    – Aranlyde
    May 15 '19 at 13:04
0
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I found this one:

$1+3+4+5+6+9=28$

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