Find GC ...it is a concatenated number
Given:
N + U + M + B + E + R = GC
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$\begingroup$ Unique solution $\endgroup$– UvcMay 15, 2019 at 8:42
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1$\begingroup$ why use the letters G and C in particular? $\endgroup$– JMPMay 15, 2019 at 8:45
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1$\begingroup$ but it hasn't got a unique solution $\endgroup$– JMPMay 15, 2019 at 8:49
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$\begingroup$ tkcs-collins.com/truman/alphamet/alpha_solve.shtml you may use this for alphametric. $\endgroup$– OrayMay 15, 2019 at 8:58
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$\begingroup$ Cryptography tag must be included for unique solution..please do not remove the tag $\endgroup$– UvcMay 15, 2019 at 8:59
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2 Answers
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This alphametic has numerous solutions. The couple I've found so far are
$1 + 3 + 4 + 5 + 6 + 8 = 27$
$1 + 4 + 5 + 6 + 7 + 9 = 32$
All other permutations of $N, U, M, B, E, R$ also work, as addition is commutative.
Edit:
Assume A1Z26.
$14 + 21 + 13 + 2 + 5 + 18 = 73$
This is a unique solution, given these constraints and the new tag.
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1$\begingroup$ Unfortunately, people have been editing tags without understanding the question. Original tags say only include cryptography $\endgroup$– UvcMay 15, 2019 at 9:08
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I found this one:
$1+3+4+5+6+9=28$
