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The only part that doesn't have an answer yet is Part II! Chop, chop!

You finally are able to get out of the airport after quickly solving the mystery. You are becoming quite the detective! Only...

you find another clue hidden in your suitcase after you arrive at your dwelling. That clever little guy! clue page
Apparently, solving this puzzle will lead you to him. You thought he was in Chad, but it looks like he has hidden somewhere else. You'd better get cracking!

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    $\begingroup$ Could you provide a transcript? Copying ciphertext characters out by hand does not add to the fun or the challenge of solving a puzzle... $\endgroup$
    – Gareth McCaughan ♦
    May 14, 2019 at 0:16
  • $\begingroup$ @GarethMcCaughan u can use OCR :) $\endgroup$
    – Omega Krypton
    May 14, 2019 at 0:17
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    $\begingroup$ I used an extremely advanced neural network designed by a lengthy evolutionary algorithm. $\endgroup$
    – Gareth McCaughan ♦
    May 14, 2019 at 0:24

1 Answer 1

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You should go to

Switzerland.

The message

consists entirely of even-length "words", composed of a repertoire of only 22 distinct pairs of letters. Replacing each of these with a unique letter and solving as a simple-substitution cipher yields: IF YOU HAVE FINALLY RECOVERED THIS NOTE IT MEANS THAT THE SITUATION IS GRAVER THAN I COULD POSSIBLY HAVE IMAGINED GO TO SWITZERLAND THAT IS WHERE I WILL BE HIDING YOU WILL FIND MORE CLUES THERE.

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  • $\begingroup$ This is incredible work! Very well done, once again! $\endgroup$
    – Voldemort's Wrath
    May 14, 2019 at 1:28
  • $\begingroup$ (I will wait to accept it so you can get some upvotes.) $\endgroup$
    – Voldemort's Wrath
    May 14, 2019 at 1:29
  • $\begingroup$ That's fine; accept as soon or as late as you please. $\endgroup$
    – Gareth McCaughan ♦
    May 14, 2019 at 1:46
  • $\begingroup$ Do you want to take a shot at Part II again? You're really close! (I feel like I'm just advertising, at this point :P) $\endgroup$
    – Voldemort's Wrath
    May 14, 2019 at 1:48
  • $\begingroup$ Well, I found an error in my calculations that changes my answer slightly. I assume it's wronger than that, though. $\endgroup$
    – Gareth McCaughan ♦
    May 14, 2019 at 1:54

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