0
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To call it a Prime.

S, N, O are 3 distinct digits that are to be determined by you so that their conclusion is right

Full concatenated number: SNOSNOS

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closed as too broad by Alconja, Peregrine Rook, Omega Krypton, PiIsNot3, Glorfindel May 7 at 4:53

Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

  • $\begingroup$ I'm afraid it's unclear what you are asking.. $\endgroup$ – athin May 5 at 4:00
  • $\begingroup$ Figuring out the prime number which corresponds to snosnos $\endgroup$ – Uvc May 5 at 4:05
  • 1
    $\begingroup$ If the answer provided thus far is the answer then this would be far too broad a question and far too mechanical a solution path to be an on-topic puzzle here. I hope there's more to it than meets the eye; but if there is, it's too subtle for me. You might want to make the puzzle a bit more explicit, so folks have an inkling of what they're trying to solve. $\endgroup$ – Rubio May 6 at 4:01
  • $\begingroup$ @Rubio Knowing this OP, I don't think a mechanical solution path (computer program) would be expected. But there might be a criterion missing in the question, as usually there's only one single solution to their puzzles. $\endgroup$ – Rand al'Thor May 23 at 11:29
3
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I ran it through a program and it spat these out as the possibilities:

1231231
1261261
1281281
1381381
1491491
1581581
1621621
1641641
1671671
1731731
1741741
1791791
1821821
1831831
1851851
1861861
1921921
1941941
1951951
3253253
3283283
3563563
3763763
3853853
3863863
3973973
3983983
9139139
9149149
9239239
9269269
9319319
9379379
9419419
9439439
9679679
9689689
9829829
9839839
9859859
9869869

I checked some at random against a list so I think they're correct.

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  • $\begingroup$ I'm intrigued that there are no solutions starting/ending in 7. Is there a simple explanation? $\endgroup$ – IanF1 May 5 at 20:15
  • $\begingroup$ Oh of course, the remaining part is a multiple of 1001 which is a multiple of 7. $\endgroup$ – IanF1 May 5 at 20:16

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