I have split the 26 letters of the alphabet into 4 sets. Here they are:

Set 1: $F G J L N P Q R S Z$
Set 2: $A M T U V W Y$
Set 3: $B C D E K$
Set 4: $H I O X$

Can you determine on what basis have I split them?

  • 3
    $\begingroup$ N, S, Z could form a set of their own. $\endgroup$
    – Florian F
    Jan 27 '15 at 11:16
  • $\begingroup$ @FlorianF I was actually thinking the same, which caused me to hesitate about my answer, until I noticed what I was missing with those. But yeah, they should have had their own. $\endgroup$ Jan 27 '15 at 11:17

My guess:

I think you have split them based on symmetry. The first group has no real symmetry, while the second group can be divided by drawing a line from top to bottom. The third group can be splitted by drawing a horizontal line from left to right, and the last group can be divided using either a vertical or horizontal line.

  • $\begingroup$ But N,S, and Z is symmetrical over a point in the middle. $\endgroup$
    – Taemyr
    Jan 29 '15 at 14:39
  • $\begingroup$ @Taemyr I know - but they are not symmetrical by drawing a line either horizontally or vertically: Therefore I said that the first group has no real symmetry. $\endgroup$ Jan 29 '15 at 14:42
  • 2
    $\begingroup$ @KevinVoorn What you mean to say is that they have no reflectional symmetry. $\endgroup$
    – Otaia
    Jan 29 '15 at 16:11
  • $\begingroup$ @Otaia Exactly, English is not my native language :3 $\endgroup$ Jan 29 '15 at 16:15

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.