Here’s another different one. You must find as many mates in 4 as possible. Include shorter ones if you want that you find, but at least one mate in four has to be included in your answer. But no computers are allowed! This is a challenge for your brain only!

Also assum that black plays perfectly.

Number Of Moves To Make: 4

Side To Move And Mate: White

The Position:

enter image description here

Good luck!

  • $\begingroup$ I just gotta say this puzzle got significantly easier once you edited because you don't have to deal with the queen and an extra rook now. $\endgroup$ – Nick Vitha Apr 23 at 23:20
  • 1
    $\begingroup$ Nahhhhhh!!!!! ;D $\endgroup$ – Rewan Demontay Apr 23 at 23:27

One forced mate in 4:

1. c8=N+ Rxc8
2. dxc8=N+ Ka8
3. Nb6+ Ka7
4. Ra8#

There’s also a mate in 1 (probably unintentional by the OP, but it’s still valid):

1. Bf2#

And a smattering of mates in 3 along the lines of Gareth McCaughan’s solution, but I can’t seem to find any other mates in 4.

  • $\begingroup$ Damn it, I was just writing that one down, after grumping a bit at OP changing the puzzle after I solved it. Oh well, never mind. $\endgroup$ – Gareth McCaughan Apr 23 at 23:16
  • $\begingroup$ Ah, that really sucks! Have a consolation +1 from me :) $\endgroup$ – PiIsNot3 Apr 23 at 23:18
  • $\begingroup$ No consolation prizes necessary; it's just a thing that happens. (Thanks, though.) $\endgroup$ – Gareth McCaughan Apr 23 at 23:24
  • $\begingroup$ Oh, there’s still other mates in 4 to find alright! ;D And I knew about that in one-I just didn’t care enough. $\endgroup$ – Rewan Demontay Apr 23 at 23:31

Here's one. (Assuming I'm not missing something; I am taking [no-computers] seriously and attempting to do it in my head.)

1. Rxa8+ Kxa8 [Black has no other legal move here]
2. d8=Q+ Ka7 [if Rxb8 then 3. cxb8=Q#]
3. Qb8+ Rxb8 [Black has no other legal move here]
4. cxb8=Q#

[EDITED to add:] After I posted this, OP changed the diagram substantially and of course the solution is no longer valid. (Because it's now a mate in 3 and for reasons I don't entirely understand OP wants only mates whose worst case is exactly 4 moves long.)

  • 1
    $\begingroup$ Sorry, I forgot something in the diagram. $\endgroup$ – Rewan Demontay Apr 23 at 23:07

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