Some minor misunderstanding last week inspired me on creating this puzzle. Hope it would be not very boring :)
Sequence:
10 50 100 306 356 562 ...
What`s next?
Hint:
RUR
$\begingroup$
$\endgroup$
1
-
$\begingroup$ Has a correct answer been given? If so, please don't forget to $\color{green}{\checkmark \small\text{Accept}}$ it. If not, a response to the answerer to help steer them in the right direction would be helpful. $\endgroup$– Rubio ♦Apr 21 '19 at 7:41
Add a comment
|
$\begingroup$
$\endgroup$
Is it
612 ?
Why I think so:
the given numbers in binary are:
1010
110010
1100100
100110010
101100100
1000110010
So the next would be: 1001100100 which in decimal equals 612
However, it would look nicer if the 10 was left out or replaced by 12 (1100) (assuming I'm not totally mistaken with my guess)
Edit: I found a second pattern (with the same outcome)
In hexadecimal numbers we get:
(A)
32
64
132
164
232
and finally 264
Bonus:
RUR = Rossum's Universal Robots
$\begingroup$
$\endgroup$
After the first digit, the sequence goes
with an alternate difference of 50 and 206
As
100-50=50
306-100=206
356-306=50
562-356=206 and so on
The next number will be
with a difference of 50.
