Finally, someone has figured it out. Good job.
I believe the answer is
I replaced letters with numbers (A=1, B=2, C=3 and D=4) as well edges in shapes with numbers (circle = 0, line = 1, triangle = 3 and square = 4). The sum of letters and the sum of the edges matches in each row. For example the first row: B+D+B+D=2+4+2+4=12 Square+Line+Triangle+Square=4+1+3+4=12 EDIT: It's also true for columns.
Ok, this is my second attempt! The answer is:
Consider giving each letter and shape a value like this: A=4, B=3, C=2, D=1, Rectangle=Circle=2 and Triangle=Line=anything!
if we add the values in each row, we get these numbers: First row=18+Line+Triangle=18+2*Line/Triangle.- Second row=18+2*Lines=18+2*Line/Triangle.- Fourth row=18+2*Lines=18+2*Line/Triangle.
considering the third row has the same value, it should also be like 18+2*Line/Triangle. So far, it is 14+1*Triangle, so the only option that can make it 18+2*Line/Triangle, is option 3.
I believe the answer is:
3 (a.k.a: C or option number 3)
I believe that the crosses and circle, and all that are just trying to fool you. So if you take those out, and put the normal numbers assigned to each letter (D is to 1, B is to 2, etc.), you will see a pattern going horizontally:
First row: 2, 1, 2, 1
Second row: 1, 2, 3, 4
Third row: 2, 2, ?(3), 3
Fourth row: 3, 3, 1, 1
Here you can see and obvious pattern. Then for the question mark, the pattern comes in duos: Two 2s, and Three 3s. That means the missing number is 3, and since the C is 3, the missing square is the C one.
This might be a heck of a stretch..
If you count each unique symbol as a note on sheet music and use the slashes to determine sharp/flat, and then you use the letters to determine length of the note (quarter, half, whole, etc.) it creates _____ some unrecognizable music as far as I can tell. However, the only one that would fit with 4/4 music is :
selection 4, (A).
Then for the shapes
and for the letters
You can see symmetric pattern formed by the shapes, as well as the letters in each column have 2 B's , 1 C, 1 D except the right most column
The answer is
There are 8 pairs in this picture. Each square gets paired with another one, if they have only ONE difference (either shape or letter).
For example, if we number each square from 1 to 16, top left to bottom right, we can see that these numbers are paired: (1,12), (2,14), (3,9), (5,8), (6,10), (7,13), (15,16). Then the only pair left is (4,11) and the only option that can be paired with square 4, is option 2.
I believe that forms that are added to the letters are not relevant to sample detection.
The letters can be replaced by numbers in two ways (A = 1, B = 2, C = 3, D = 4)
2 4 2 4
4 2 3 1
2 2 1 3
3 3 4 4
or (A = 4, B = 3, C = 2, D = 1)
3 1 3 1
1 3 2 4
3 3 4 2
2 2 1 1
irrespective of how the letters are replaced by numbers, the sum of the two rows from the top and bottom are equal, such as the same are sums of the two columns on the right and on the left.
So the answer:
number 4 is correct (A missing)