I have tried to solve few number series problems but this one is little difficult for me to solve. kindly help me to solve this.
-1,35,143,323,?
Thanks in advance.
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$\begingroup$ Hm.. Maybe the first number should be $6$ instead of $-1$? $\endgroup$– athinMar 21, 2019 at 13:47
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4$\begingroup$ This looks like this puzzle may have been taken from somewhere (v.s. one you created) - if so please provide attribution to the source. And welcome to Puzzling SE! $\endgroup$– PartyHatPandaMar 21, 2019 at 14:05
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2 Answers
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I think I got this:
0*0 -1 = -1
6*6 -1 = 35
12*12-1 = 143
18*18 -1 = 323
24*24 -1 = 575
or:
(6*0)^2 -1 = -1
(6*1)^2 -1 = 35
(6*2)^2-1 = 143
(6*3)^2 -1 = 323
(6*4)^2 -1 = 575
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$\begingroup$ Or Maybe there is a Shorter way that im missing $\endgroup$– BediMar 21, 2019 at 13:51
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$\begingroup$ My comment might be confusing after the edit so I removed it, but +1 from me now $\endgroup$ Mar 21, 2019 at 14:29
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1$\begingroup$ @OHO That's neat. It holds true in math that $x^2 = (x + y)(x - y) + y^2$. In this instance $y$ is just 1 in every case; so it's the same equation, just a different representation. You may have known that already, just thought it was interesting. $\endgroup$ Mar 21, 2019 at 20:53
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Bedi’s got the idea. Another way to write it would be:
(6n)^2 - 1 where n goes from 0 to 4
So, the next number is
(6*4)^2 - 1 = 575
