# Find the next value of this number series [closed]

I have tried to solve few number series problems but this one is little difficult for me to solve. kindly help me to solve this.

-1,35,143,323,?


• Hm.. Maybe the first number should be $6$ instead of $-1$? Mar 21, 2019 at 13:47
• This looks like this puzzle may have been taken from somewhere (v.s. one you created) - if so please provide attribution to the source. And welcome to Puzzling SE! Mar 21, 2019 at 14:05

I think I got this:

0*0 -1 = -1
6*6 -1 = 35
12*12-1 = 143
18*18 -1 = 323
24*24 -1 = 575

or:

(6*0)^2 -1 = -1
(6*1)^2 -1 = 35
(6*2)^2-1 = 143
(6*3)^2 -1 = 323
(6*4)^2 -1 = 575

• Or Maybe there is a Shorter way that im missing
– Bedi
Mar 21, 2019 at 13:51
• My comment might be confusing after the edit so I removed it, but +1 from me now Mar 21, 2019 at 14:29
• Or (-1)x1, 5x7, 11x13, 17x19, 23x25, ...
– OHO
Mar 21, 2019 at 16:44
• @OHO That's neat. It holds true in math that $x^2 = (x + y)(x - y) + y^2$. In this instance $y$ is just 1 in every case; so it's the same equation, just a different representation. You may have known that already, just thought it was interesting. Mar 21, 2019 at 20:53

Bedi’s got the idea. Another way to write it would be:

(6n)^2 - 1 where n goes from 0 to 4

So, the next number is

(6*4)^2 - 1 = 575