-2
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[$s$]   [$u$]  [$r$]  [$q$]  [$22$]  [$r$] , [$q$]  [$22$]  [$p+2k$]  [$100-7k$] ,
[$q$]  [$k$]  [$3q$]  [$t$]  [$100-r$]  [$u$] , [$21$]  [$p+s-k$]  [$q$]  [$3p+k$]  [$23$] ,
[$p+s$]  [$22$][$2p+s$]  [$u$]  [$s$]  [$4s$]  [$u$] , [$k$]  [$r-s+k$] [$100-r-s$] [$p$] [$3q$][$12$],
[$q$] [$100-r$] [$u-s$] [$23$] [$p$] [$12$][$r$] [$t$].
                                              -x

[  ] lies between 1 and 100(extremes included)
$p+q+r+s+t+u+k=199$

$p,q,r,s,t,u,k$ are all distinct
$p,q,s,t,k$ are odd,
$r,u$ even

$q,t$ are primes
$u$ is largest
$k$ is smallest

The multiple $p\times q\times r\times s\times t\times u\times k$ does not have any of $p,q,r,s,t,u$ or $k$.

Hint:

Extremes included can mean that either p,q,r,s,t,u,k ...is 1 or 100...

Hint2:

22 = 'GO'

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  • $\begingroup$ I don’t understand the question. What does -x have to do with the comma-delimited, dot-terminated preceding set of 7 products? $\endgroup$ – Lawrence Mar 19 at 15:00
  • $\begingroup$ @Lawrence It has some purpose. Any further details would defeat that purpose. $\endgroup$ – peerless Mar 20 at 6:22
  • $\begingroup$ A further hint might be warranted. $\endgroup$ – Rubio Mar 28 at 5:20
  • $\begingroup$ @Rubio Added... $\endgroup$ – peerless Mar 29 at 9:09
2
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I feel like there is more to it than this, as I'm not sure how the X comes into play, but...

Possible values are: $p=23$, $q = 31$, $r = 16$, $s = 25$, $t = 37$, $u = 54$, and $k = 13$. Each of the values exist within brackets, so they need to be inclusively between 1 and 100. The operations within the brackets ($100-7k$, $100-r$, $r-s+k$, etc.) all also lie inclusively between 1 and 100. Following the rest of the parameters - $p+q+r+s+t+u+k \rightarrow 23+31+16+25+37+54+13=199$, they are all distinct, $p,q,s,t,k$ are odd and $r,u$ are even, $q,t$ are primes, $u$ is the largest and $k$ is the smallest. Finally, $p\times q\times r\times s\times t\times u\times k = 23\times 31\times 16\times 25\times 37\times 54\times 13=7407784800$, which doesn't have any of the numbers within it.

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  • $\begingroup$ Solving each set of brackets, you end up with 25 54 16 31 22 16 | 31 22 49 9 | 31 13 93 37 84 54 | 21 37 31 82 23 | 48 22 71 54 25 100 54 | 13 4 59 23 93 12 | 31 84 39 23 23 12 16 37. There are 20 distinct values there. Assigning each distinct value to a letter, I get ABCDEC DEFG DHIJKB LJDMN OEPBAQB HRSNIT DKUNNTCJ. If this is enciphered somehow, it's not a simple cryptogram (or at least not one that quipqiup can solve). $\endgroup$ – GentlePurpleRain Mar 18 at 21:05
  • 2
    $\begingroup$ It looks formatted like a quote to me. Maybe when the cipher is solved, it will be a quote that can be attributed to 'x' which is the name of a person. $\endgroup$ – TwoBitOperation Mar 20 at 14:44

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