-1
$\begingroup$

[$s$]   [$u$]  [$r$]  [$q$]  [$22$]  [$r$] , [$q$]  [$22$]  [$p+2k$]  [$100-7k$] ,
[$q$]  [$k$]  [$3q$]  [$t$]  [$100-r$]  [$u$] , [$21$]  [$p+s-k$]  [$q$]  [$3p+k$]  [$23$] ,
[$p+s$]  [$22$][$2p+s$]  [$u$]  [$s$]  [$4s$]  [$u$] , [$k$]  [$r-s+k$] [$100-r-s$] [$p$] [$3q$][$12$],
[$q$] [$100-r$] [$u-s$] [$23$] [$p$] [$12$][$r$] [$t$].
                                              -x

[  ] lies between 1 and 100(extremes included)
$p+q+r+s+t+u+k=199$

$p,q,r,s,t,u,k$ are all distinct
$p,q,s,t,k$ are odd,
$r,u$ even

$q,t$ are primes
$u$ is largest
$k$ is smallest

The multiple $p\times q\times r\times s\times t\times u\times k$ does not have any of $p,q,r,s,t,u$ or $k$.

Hint:

Extremes included can mean that either p,q,r,s,t,u,k ...is 1 or 100...

Hint2:

22 = 'GO'

Hint3:

s 9 || q 19 || u 56 || r 52 || k 1 || t 29 || p 33

$\endgroup$
  • $\begingroup$ I don’t understand the question. What does -x have to do with the comma-delimited, dot-terminated preceding set of 7 products? $\endgroup$ – Lawrence Mar 19 '19 at 15:00
  • $\begingroup$ A further hint might be warranted. $\endgroup$ – Rubio Mar 28 '19 at 5:20
  • $\begingroup$ @Rubio Added... $\endgroup$ – peerless Mar 29 '19 at 9:09
  • $\begingroup$ Another hint added $\endgroup$ – peerless Nov 20 '19 at 17:37
  • 1
    $\begingroup$ X is a poet.... $\endgroup$ – peerless Nov 21 '19 at 18:54
5
$\begingroup$

x is:

The poet, William Butler Yeats.

And the puzzle itself is:

A rendering of his poem, The Lake Isle of Innisfree, where each word has been replaced by a number repesenting its value in A1Z26.

I was only able to work this out after Hint 3 gave away the values of s, q, u, r, k, t and p. Plugging these into the mathematics gave:

9-56-52-19-22-52,
19-22-35-93,
19-1-57-29-48-56,
21-41-19-100-23,
42-22-75-56-9-36-56,
1-44-39-33-57-12,
19-48-47-23-33-12-52-29.

Armed with the knowledge from Hint 2:

We know that some of the 22's can be replaced by 'GO'. In A1Z26 'GO' is worth 22 points. Coincidence? I thought not... So I tried calculating the A1Z26 values of common words like 'and' and 'the' and slotted those in where they fitted, noting particularly that 1 would likely be A and 9 I:

I-56-52-and-go-52,
And-go-to-93,
And-a-57-29-48-there,
Of-41-and-100-23,
42-(go)-75-56-I-36-there,
A-44-for-the-57-12,
And-48-47-in-the-12-52-29.

Finally, Google was my friend!

Searching for poem "and go to" led me to The Lake Isle of Innisfree and all numeric values panned out!

I will arise and go now,
And go to Innisfree,
And a small cabin build there,
Of clay and wattles made,
Nine bean rows will I have there,
A hive for the honey bee,
And live alone in the bee-loud glade.

BOOM! Which all meant that 'x' must be:

Its creator, the poet William Butler Yeats, since this is how a poet's name often appears at the end of their published work, following a short dash. Phew, solved!

$\endgroup$
3
$\begingroup$

I feel like there is more to it than this, as I'm not sure how the X comes into play, but...

Possible values are: $p=23$, $q = 31$, $r = 16$, $s = 25$, $t = 37$, $u = 54$, and $k = 13$. Each of the values exist within brackets, so they need to be inclusively between 1 and 100. The operations within the brackets ($100-7k$, $100-r$, $r-s+k$, etc.) all also lie inclusively between 1 and 100. Following the rest of the parameters - $p+q+r+s+t+u+k \rightarrow 23+31+16+25+37+54+13=199$, they are all distinct, $p,q,s,t,k$ are odd and $r,u$ are even, $q,t$ are primes, $u$ is the largest and $k$ is the smallest. Finally, $p\times q\times r\times s\times t\times u\times k = 23\times 31\times 16\times 25\times 37\times 54\times 13=7407784800$, which doesn't have any of the numbers within it.

$\endgroup$
  • $\begingroup$ Solving each set of brackets, you end up with 25 54 16 31 22 16 | 31 22 49 9 | 31 13 93 37 84 54 | 21 37 31 82 23 | 48 22 71 54 25 100 54 | 13 4 59 23 93 12 | 31 84 39 23 23 12 16 37. There are 20 distinct values there. Assigning each distinct value to a letter, I get ABCDEC DEFG DHIJKB LJDMN OEPBAQB HRSNIT DKUNNTCJ. If this is enciphered somehow, it's not a simple cryptogram (or at least not one that quipqiup can solve). $\endgroup$ – GentlePurpleRain Mar 18 '19 at 21:05
  • 3
    $\begingroup$ It looks formatted like a quote to me. Maybe when the cipher is solved, it will be a quote that can be attributed to 'x' which is the name of a person. $\endgroup$ – TwoBitOperation Mar 20 '19 at 14:44

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.