I am stuck as below image. Can this be solved ?
1
$\begingroup$
$\endgroup$
6
$\begingroup$
$\endgroup$
Yes. This is a 3-cycle of the corners, and all three of those corners also need a twist in the same direction. Both of these things can be done individually.
I put that position into Cube Explorer, and it gave the move sequence R' F U2 F' R F R' U2 R F'.
answered Mar 7 at 7:31
-
$\begingroup$ Could you recommmend a good link to a description of the sequence notation? $\endgroup$ – BmyGuest Mar 7 at 19:33
-
1$\begingroup$ @BmyGuest This standard notation (Singmaster notation) is explained in lots of places, for example in the speedsolving.com wiki. $\endgroup$ – Jaap Scherphuis Mar 7 at 22:03
2
$\begingroup$
$\endgroup$
It can be solved.
This seems to be the antisune case which can be solved with the algorithm:
R U2 R' U' R U' R'
-
$\begingroup$ welcome here, nice first answer +1! edited spoilers for you ;) $\endgroup$ – Omega Krypton Mar 24 at 5:39
-
$\begingroup$ That anti-sune will orient the corners, but not permute them. It will also perform a 3-cycle of the edges, so after the anti-sune you will still have to be permute both edges and corners to solve it. $\endgroup$ – Jaap Scherphuis Mar 24 at 12:40
