The following sequence was given to me by one of my friend:
$$\color{red}{2 \star 8 \star 8 = 161642}$$ $$\color{blue}{4 \star 9 \star 7 = 362843}$$ $$\color{red}{7 \star 5 \star 9 = 356344}$$ $$\color{blue}{9 \star 6 \star 8 = 547245}$$ $$\color{red}{5 \star 7 \star 9 = 354546}$$ $$\color{blue}{3 \star 9 \star 9 = 272748}$$ $$\color{red}{4 \star 8 \star 9 = \text{M}}$$ $\color{red}{\text{M}}$ = ?
My Thoughts:
The first two digits of R.H.S can be found by $a.b$ , where L.H.S = $a \star b \star c$ ,
i.e, For 1st relation: $2.8=16 = 1^{st}$ two digits of $\color{green}{16}1642$
Similarly,the second two digits of R.H.S can be found by $a.c$ , where L.H.S = $a \star b \star c$ ,
i.e, For 2nd relation: $4.7=28 = 2^{nd} $ two digits of $36 \color{green}{28}43$
$$\implies M= 3236 \, \_ \, \_$$
How do I find the $3^{rd}$ two digits of R.H.S?