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Construct expressions that equal $31$, $32$, $33$, and $34$ using the numbers $1$, $2$, $6$, and $7$. In each expression, each number must be used exactly once. You addition ($+$), subtraction ($-$), multiplication ($\times$), and division ($\div$). You may also use parentheses.

I have found several ways to do this for 33 but not for the other answers.

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  • $\begingroup$ Hi welcome to Puzzling SE! These kinds of questions might be a little too math-y for the sight, but I would need verfied inputs from more experienced users $\endgroup$ – North Mar 5 at 5:09
  • $\begingroup$ @North this just seems like your typical "use these numbers and these operations to make this total" puzzle to me $\endgroup$ – Hugh Mar 5 at 5:16
  • $\begingroup$ @Hugh I guess I'll retract my flag then since it's not off-topic per se...? Or should I keep the flag? $\endgroup$ – North Mar 5 at 5:17
  • $\begingroup$ @North I'd say retract, I guess? It's basically like one of these puzzles, but with $1$, $2$, $6$, and $7$, and different totals. [edit: JonMark Perry added the tag formation-of-numbers, I think that tag suits the puzzle well.] $\endgroup$ – Hugh Mar 5 at 5:20
  • $\begingroup$ Okay, I've retracted the flag, but in all honesty (I'm sorry to say this) but I'm still not a huge fan of these puzzles. $\endgroup$ – North Mar 5 at 5:22
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$31=(7-2)\times6+1$
$32=(7+1)\times(6-2)$
$33=7\times(6-1)-2$
$34=(7-1)\times6-2$

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