Eight boxes, A, B, C, D, E, F, G, and H are kept one above another not necessarily in the order above.

  • Three boxes are between H and G and neither of them is at the top or bottom position.
  • Two boxes are between F and C and box F is above box C.
  • Two boxes are between G and C.
  • The number of boxes between A and H is same as the number between A and G.
  • Box D is above box E and more than one box is between D and E.
  • Box E is not at the bottom position.


Is the answer to the above question:

  • $\begingroup$ Yeah! that's the answer. $\endgroup$ Feb 6, 2019 at 13:53

2 Answers 2


Yes, I believe that this is the only solution. My reasoning, which I'm sure is what you had, but to reaffirm:

Reasoning (note: Top->Bottom, (#) is the clue sentence):

Using clues (2) and (3), the only options are _F__C__G or F__C__G_. Since G is not the bottom (1), it's the latter.

Then it follows:

H must be 3 above G (1): F_HC__G_. A must be (4) F_HCA_G_. Based on (5 & 6): FDHCAEG_

And finally:

FDHCAEGB (the only possible answer)


D 4.
G 1. 3.
A 3.
F 2.
H 1. 3.
E 4.
C 2.
There may be more possible solutions. The numbers point to the hints given!
B was not mentioned, so I left B at an empty place.

  • $\begingroup$ Hi Anders, welcome to Puzzling! Please hide your answer using the spoiler tag (">!"). Also, can you clarify your answer and expand on your logic, please? I'm having a hard time reading it in the current format and I'm unsure how you reached all of your conclusions (for example, G and C should have 2 boxes between them, but your answer seems to have 5 between them). Thanks and happy puzzling! $\endgroup$ Feb 6, 2019 at 14:18

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