1 = 1
2 = 12
3 = 27
4 = 44
5 = 35
6 = ?
The only hint I got was:
“Think outside the box”
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2$\begingroup$ Hi MA8, welcome to PSE! What is the source of the puzzle? $\endgroup$– eye_am_grootFeb 5, 2019 at 18:39
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$\begingroup$ Hi Greg, I actually have no reliable source for the puzzle. My friend gave it to me and he’s a puzzle addict, and I have been trying to figure the answer since three days. I gave up so I thought I could get help here! $\endgroup$– MA8Feb 5, 2019 at 18:50
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$\begingroup$ Gotcha. No problem! Hope you get your answer! $\endgroup$– eye_am_grootFeb 5, 2019 at 18:53
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$\begingroup$ Could you perhaps list some of the possibilities or sequence rules you might have already tried? $\endgroup$– visualnotsobasicFeb 5, 2019 at 19:15
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$\begingroup$ I tried thinking of a mathematical formula for the sequence, none worked (I even used a computer to assist me). Then I came back to the hint and tried thinking about the words themselves: “one” “two” and so on, and I still can’t find a solution... But I am 90% sure it is not a mathematical sequence formula. $\endgroup$– MA8Feb 5, 2019 at 19:33
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Show 5 more comments
1 Answer
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I think the answer might be
$6 = 816$
Reasoning
I think they are all Platonic numbers from a specific branch.
1 = 1, the first Platonic number in all branches
2 = 12, the second icosahedral number
3 = 27, the third cube number
4 = 44, the fourth octahedral number,
5 = 35, the fifth tetrahedral number.
Therefore, we must have
6 = 816, the sixth dodecahedral number
since this is the only remaining option.
Hint
"Think outside the box" could refer to the idea of thinking about Platonic numbers beyond cubes.
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$\begingroup$ The values start with basically (1)
Rank 4 -Dodecahedraland go up to (5)Rank 0 -Tetrahedral$\endgroup$ Feb 6, 2019 at 15:03 -
$\begingroup$ So it could be either
146or816with6starting the cycle over again or just reflecting back down the Ranks $\endgroup$ Feb 6, 2019 at 15:07 -
$\begingroup$ This is the most answer that makes sense until now. Thank you very much! $\endgroup$– MA8Feb 6, 2019 at 19:11
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$\begingroup$ Also...since all N forms have 1...it could be assumed that the sequence starts with
Dodecahedraland goes up thervalues...the only option after5is to either reflect or start all over from the "beginning $\endgroup$ Feb 7, 2019 at 18:44