Using only the numbers
1, 2, 3, 4, 5, 6, 7, 8, 9 and 0
With only addition can you make a sum of 100?
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Sign up to join this communityUsing only the numbers
1, 2, 3, 4, 5, 6, 7, 8, 9 and 0
With only addition can you make a sum of 100?
This is mathematically impossible. I think EmbodimentofIgnorance was trying to tell us this, but didn't explain it.
Basically, no matter what order you try to put the answers into, it'll never actually become $100$ — it'll always be $99$, because the numbers add up to be multiples of nine. Consider this:
When you add up all numbers $0$–$9$, it'll be $45$ — a multiple of $9$.
Now obviously, $45$ is too small, so you're gonna have to make some two digit numbers (e.g. $45$, $67$, $13$, etc.)
Now this gets a little funky, so bear with me.
Let's assume you use the value of $34$ instead of $3+4$. You'll notice that you'll get a multiple of nine when you subtract the number by the ones you were using (so $34-3-4=27$).
Now, going back to the total, it becomes $45-3-4+34 = 72$.
You subtract the three and the four, because those numbers are being used for $34$. Keep in mind that order doesn't matter, because it's essentially just $45-7$.
No matter what pair you decide to choose, it'll always turn out to be a multiple of $9$.
The closest I can get is this:
90 + 1,765 + 8,234 = 99,999
Like north said also only a multiple of 9