1
$\begingroup$

Help me solving this sequence: need help 9,?,342,675,1230, ?,3561,5892

Source: http://zagaza.ru/za548.htm

$\endgroup$
4
$\begingroup$

The full sequence is

9, 120, 342, 675, 1230, 2118, 3561, 5892

Reasoning

The difference between consecutive terms is $111$ times the $n$th Fibonacci number $$ 9 + 111 = 120$$ $$120 + 222 = 342$$ $$ 342 + 333 = 675$$ $$ 675 + 555 = 1230$$ $$ 1230 + 888 = 2118$$ $$ 2118 + (13\times111) = 3561$$ $$ 3561 + (21 \times 111) = 5892$$ And the next term would be $$ 5892 + (34 \times 111) = 9666$$

$\endgroup$
-3
$\begingroup$

i think the first answer is 120.

$\endgroup$
  • 2
    $\begingroup$ please explain your answer. thanks! $\endgroup$ – Omega Krypton Jan 13 at 5:17

Your Answer

By clicking "Post Your Answer", you acknowledge that you have read our updated terms of service, privacy policy and cookie policy, and that your continued use of the website is subject to these policies.

Not the answer you're looking for? Browse other questions tagged or ask your own question.