2
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When I doing the IQ paper last Sunday, I found an interesting question. Using that I made a different puzzle.

enter image description here

Hint 01:

Middle number of each row build using the number before and after it. Eg: 13 built using 25 & 43.

Hint 02:

4th row will be 55 73 73 & 5th row will be 65 36 83

Hint 03:

If the 1st and last number of any row include the same letters with opposite like 35 and 53 (3 & 5 letters are in both), a middle number will have definitely same letters like 66 (11,22,33, etc)

Hint 04:

I had done a mistake when writing last hint(last row of the grid.). I am really sorry about that, but you can get another hint from how I correct my mistake. I mean which numbers I have changed to correct my mistake... I will write the correct answer tomorrow.


Text version:

25 13 43
35 66 53
45 -- 63
55 73 73
65 36 83
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  • $\begingroup$ Regarding your hint - my answer uses just that. $\endgroup$ – rhsquared Jan 7 at 11:24
  • $\begingroup$ @rhsquared Replied it to... And I added another hint $\endgroup$ – I am the Most Stupid Person Jan 7 at 12:15
  • $\begingroup$ Are you sure there isn't a typo in the hint 2? $\endgroup$ – rhsquared Jan 7 at 12:28
  • $\begingroup$ It is sure... There is no typo in hint 2. I will give one more hint for you... If the 1st and last number include the same letters with opposite like 35 and 53 (3 & 5 letters are in both), a middle number will have definitely same letters like 66 (or 11,22,33, etc). $\endgroup$ – I am the Most Stupid Person Jan 7 at 12:35
  • $\begingroup$ what would line 6 look like? $\endgroup$ – JonMark Perry Jan 7 at 14:21
5
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For the first line:

2 * 5 = 10, 1 + 0 = 1 gives the first digit of the middle number
4 * 3 = 12, 1 + 2 = 3 gives the second digit of the middle number

This rule works for all, so the answer is:

4 * 5 = 20, 2 + 0 = 2
6 * 3 = 18, 1 + 8 = 9
29.

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  • 1
    $\begingroup$ I think this is your first answer to this site. It is correct. Good work !!!! $\endgroup$ – I am the Most Stupid Person Jan 8 at 5:35
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If we name the columns $A, B, C$ we can do the following:
$ABS((A1 + C1)/2 - B1) = ABS((25+43)/2 - 13) = 21$
$ABS((A2 + C2)/2 - B2) = ABS((35+53)/2 - 66) = ABS(-22) = 22$
Thus we can conclude that $ABS((A3 + C3)/2 - B3) = 23, or ABS(54 - B3) = 23$ and therefore
$B2$ could be either 31 or 77

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  • $\begingroup$ rot13 fbzrubj rneyvre v tbg 31 gbb ohg abg fher gb rkcynva vg $\endgroup$ – Mukyuu Jan 7 at 10:41
  • $\begingroup$ This is a good try, but there is a more accurate answer... I mean, your answers is x or y... However, this is a relly nice answer :-) $\endgroup$ – I am the Most Stupid Person Jan 7 at 12:06
0
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Possibly

31? As first row is -12 then +30, second is +31 then -13, so perhaps alternating and increasing both by 1 to give -14 then +32

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0
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119

Because:

The sum of the Row 1 value plus the Row 3 value divided by two equals the Row 2 value in each column. SO: A1(25) + A3(45) /2 = (A2) 35 AND C1(43) + C3(63) /2 = (C2)53 Therefore B1(13) + B3(119) /2 = 66

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  • $\begingroup$ I didn't take account of the hints. My answer is still wrong, despite the edits. :( $\endgroup$ – Matt Hollands Jan 7 at 14:30
-2
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33 is the answer I guess..is it crrct??

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  • $\begingroup$ please provide complete reason for your answer $\endgroup$ – Amruth A Jan 7 at 18:16
  • $\begingroup$ @user56231 Please provide reasoning as to why do you think this is the answer. Answers like this tend to get down votes. Also you need to hide your answer in a spoiler. $\endgroup$ – rhsquared Jan 7 at 19:54

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