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Can you find out what the numbers below have in common? Can you figure out what comes next?

I = 9,9,9,8,8,8,2,7,?

II = 6,6,7,5,7,5,1,3,?

III = 4,8,4,8,4,8,5,3,?

IV = 5,5,5,6,6,6,6,8,?

V = 2,8,1,4,7,2,8,6,?

VI = 9,8,7,5,4,3,3,5,?

VII = 2,0,2,0,2,0,2,0,?

VIII = 3,6,1,2,2,4,0,1,?
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    $\begingroup$ Are the 8 sequences related? Or are they separate? $\endgroup$ – Dr Xorile Nov 12 '18 at 22:53
  • $\begingroup$ They are separate. :) $\endgroup$ – danimoth Nov 13 '18 at 3:40
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    $\begingroup$ Mmm. That makes this extremely difficult. You might find it gets closed as too broad. It becomes a "guess what's in my head" if there's no connecting theme. $\endgroup$ – Dr Xorile Nov 13 '18 at 4:13
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    $\begingroup$ I believe the OP means that the eight sequences follow the same algorithm, but in different cases $\endgroup$ – Omega Krypton Nov 13 '18 at 7:39
  • $\begingroup$ Hmmm, I wonder what the 7th one is? I know! 5! (just joking) $\endgroup$ – Yout Ried Jan 5 at 5:48
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I guess the 1. solution is...

$8 * 3 = 24$, because there are three times a 9 and $9 * 3 = 27$

The 4. answer could be...

$68 + 20 = 88$, because if you erase the commas, you get $55 + 1 = 56, 56 + 10 = 66, 66 + 2 = 68$

The 5. answer could be...

$3$, because if you erase the commas, all numbers are multiples of $7$, the only 2 digit number starting with $6$ and being a multiple of $7$ is $63$

The 6. answer could be...

$98 - 75 = 23$, $75 - 43 = 32$, $43 - 35 = 8$, you can see, that the difference of the first pairs is mirrored, so maybe the next number is $35 - 8 = 27$

The 7. answer could be...

$3$, because there are $2^2 = 4$ times the number 2, separated of $0$. So my idea is, that the sequence continues with $3,0,3,0,3,0,3,0,3,0,3,0,3,0,3,0,3,0,4,0,...$

The 8. sequence could work...

like the 5. If all numbers are multiples of $3$, the last number could be $5$ or $8$, if all numbers are multiples of $6$, the last number could be $8$

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