6
$\begingroup$

The premise of the puzzle is quite simple. Here's how to set it up.

  1. Draw a 5x5 grid of squares.

  2. Write the number 1 in the middle.

  3. Make a "snake" of numbers up to 25 so that each number is orthogonal from the previous number AND the next number.

  4. Divide the grid into the pentominoes formed by the numbers 1-5, 6-10, 11-15, 16-20, and 21-25.

  5. If no two of the pentominoes are the same when rotated or reflected, you win. If two or more are, then you lose.

Example:

sorry for bad quality

This fails because 6-10 and 11-15 are the same, as are 16-20 and 21-25.

Is it possible to win this game? If your answer is no, prove it. If your answer is yes, give an example.

(I don't quite know how to tag this, feel free to edit some other tags in.)

Improve this question
$\endgroup$
1
  • $\begingroup$ I don't understand each number is orthogonal from the previous number AND the next number. Do you simply mean that n should be connected to n-1 and n+1, no matter in which direction? $\endgroup$
    – Eric Duminil
    Nov 8, 2018 at 8:13

2 Answers 2

Reset to default
8
$\begingroup$

If I understand the game correctly,

21,22,23,24,25
20,11,10, 9, 8
19,12, 1, 2, 7
18,13,14, 3, 6
17,16,15, 4, 5

Improve this answer
$\endgroup$
1
  • 1
    $\begingroup$ I had a rotation of this. Well done! $\endgroup$
    – Excited Raichu
    Nov 7, 2018 at 18:20
7
$\begingroup$

I guess, I'm too late, but I propose

[A possible way]1

Improve this answer
$\endgroup$
1
  • $\begingroup$ Nice! And looks "prettier" than mine! $\endgroup$
    – eye_am_groot
    Nov 7, 2018 at 18:27

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.