21
$\begingroup$

(It's an old soviet math problem, no tricks or anything here)


Jimmy is 21 years younger than his mother.

Six years from now, Jimmy's mother will be five times as old as Jimmy.

Where is Jimmy's father?

$\endgroup$
4
  • $\begingroup$ You should word it as "five times as old" to remove ambiguity. $\endgroup$ Nov 2, 2018 at 19:42
  • $\begingroup$ @ Thomas Blue This question was asked as " Where is Jenifer's Husband" on this site a few years ago. So it is a duplicate. Please check $\endgroup$
    – DrD
    Nov 4, 2018 at 16:27
  • $\begingroup$ @ DEEM That is true. In russian it was called "Where is the father" so my searches for duplicate proved worthless $\endgroup$ Nov 5, 2018 at 11:19
  • $\begingroup$ No issue. Happens all the time. Funny puzzle though $\endgroup$
    – DrD
    Nov 5, 2018 at 12:47

2 Answers 2

27
$\begingroup$

Well, first I have to solve the math problem, I guess.

Let $x$ equal Jimmy's age.

This means $x+21$ is the mother's starting age. In 6 years, Jimmy will be $x+6$ and his mother will be $x+27$.

So, $(x+6)*5 = x+27$

$5x+30 = x+27$

$5x + 3 = x$

$4x = -3$

$x = -3/4$

Yeah, I see where this is going. Jimmy is exactly -9 months old, which means his father is right where his mother is, most likely.

$\endgroup$
1
  • 3
    $\begingroup$ Nice! You get the tick! $\endgroup$ Nov 2, 2018 at 17:02
24
$\begingroup$

Easy math:

Let $x$ represent Jimmy's age.
Let $y$ represent Jimmy's mother's age.

We can convert this into two equations:
$x+21=y$
$5*(x+6) = y+6$

Substituting the first equation into the second equation via isolated y:
$5x+30=x+21+6$

Subtract x and 30 from both sides of the equation:
$4x = -3$

Jimmy is -3/4 years old. This is the length of a pregnancy (9 months).
Jimmy's father is currently sleeping with his mother as he is being conceived.

$\endgroup$
3
  • $\begingroup$ Looks like someone else beat me by a matter of seconds... so close $\endgroup$
    – kanoo
    Nov 2, 2018 at 15:05
  • $\begingroup$ Still nice! You get the sympathy and an upvote! $\endgroup$ Nov 2, 2018 at 17:02
  • $\begingroup$ 1 min 29 sec to be exact... @kanoo Nice job tho, +1! $\endgroup$ Feb 9, 2019 at 11:22

Not the answer you're looking for? Browse other questions tagged or ask your own question.