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I found that 3abc+a+b+c formula is correct first and second triangle. But the result for third triangle isn't in the options. Can you find another solution?

Source: It's from an old job admission exam of a bank. Can not recall bank name.


closed as off-topic by w l, Glorfindel, Chowzen, Oray, JMP Oct 22 '18 at 13:56

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  • $\begingroup$ It appears you took the question from a book. Please mention the source of the question, proper attribution is necessary, otherwise the question might be closed. $\endgroup$ – Shahriar Mahmud Sajid Oct 22 '18 at 11:41
  • $\begingroup$ it's from an old job admission exam of a bank $\endgroup$ – frkntrn Oct 22 '18 at 11:43
  • $\begingroup$ you should edit the question to include the source. $\endgroup$ – Shahriar Mahmud Sajid Oct 22 '18 at 11:45

The answer is -

D - 349


it is achieved by summing the cube of the corner digits,
as in $a^3+b^3+c^3$
$1^3 +2^3+ 2^3=17$
$3^3 +3^3+ 4^3=118$
$2^3 +5^3+ 6^3=349$


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