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I found that 3abc+a+b+c formula is correct first and second triangle. But the result for third triangle isn't in the options. Can you find another solution?

Source: It's from an old job admission exam of a bank. Can not recall bank name.

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closed as off-topic by w l, Glorfindel, Chowzen, Oray, JonMark Perry Oct 22 '18 at 13:56

This question appears to be off-topic. The users who voted to close gave this specific reason:

  • "This looks like a puzzle you found elsewhere. For content you did not create yourself, proper attribution is required. If you have permission to repost this, please edit to include (at minimum) where it came from, then vote to reopen. Posts which use someone else's content without attribution are generally deleted." – w l, Glorfindel, Chowzen, Oray, JonMark Perry
If this question can be reworded to fit the rules in the help center, please edit the question.

  • $\begingroup$ It appears you took the question from a book. Please mention the source of the question, proper attribution is necessary, otherwise the question might be closed. $\endgroup$ – Shahriar Mahmud Sajid Oct 22 '18 at 11:41
  • $\begingroup$ it's from an old job admission exam of a bank $\endgroup$ – frkntrn Oct 22 '18 at 11:43
  • $\begingroup$ you should edit the question to include the source. $\endgroup$ – Shahriar Mahmud Sajid Oct 22 '18 at 11:45
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The answer is -

D - 349

Explanation-

it is achieved by summing the cube of the corner digits,
as in $a^3+b^3+c^3$
$1^3 +2^3+ 2^3=17$
$3^3 +3^3+ 4^3=118$
$2^3 +5^3+ 6^3=349$

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